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3 years ago

Algebraic expression 6 times a number,n

Mathematics

1 answer:

trasher [3.6K]3 years ago

6 0

6 times a number n is 6n.

In algebra, when number multiply with variables, you don't need a multiplication sign (x). You just put them together like 6n (instead of 6 x n).

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tangare [24]

Answer:

Adult: 50 tickets

Child: 34 tickets

Step-by-step explanation:

Let a be the amount of adult tickets

Let c be the amount of child tickets

Equation:

a + c = 84

14a + 9c = 1,006

Step 1: Multiply a + c = 84 with -9, to canceled c.

-9 (a + c = 84) → -9a - 9c = -756

14a + 9c = 1006 → 14a + 9c = 1006

Step 2: Combined the 2 equation together, and solved it.

-9a - 9c = -756

14a + 9c = 1006

5a = 250

5 5

a = 50

Step 3: Plug 50 into the one of the equation, and solved it.

a + c = 84 → 50 + c = 84

-50 -50

c = 34

Answer: Adult tickets (a) = 50 and Child tickets (c) = 34

To check the answer plug the two number into the equation ( Make sure to add 50 for a and 34 for c).

3 0

3 years ago

How much wrapping paper did he use ,in square inches

Paul [167]

Answer:

96.76 square inches

Step-by-step explanation:

5.2x5.2=27.04

6.7x5.2/2=17.42

17.42x4=69.68

69.68+27.04=96.76

Hope this helps <3 Comment if you want more thanks and be sure to give brainliest (4 left) <3

6 0

2 years ago

Suppose x is a real number and epsilon > 0. Prove that (x - epsilon, x epsilon) is a neighborhood of each of its members; in

kaheart [24]

Answer:

See proof below

Step-by-step explanation:

We will use properties of inequalities during the proof.

Let $y\in (x-\epsilon,x+\epsilon)$ . then we have that $x-\epsilon$ . Hence, it makes sense to define the positive number delta as $\delta=\min\{x+\epsilon-y,y-(x-\epsilon)\}$ (the inequality guarantees that these numbers are positive).

Intuitively, delta is the shortest distance from y to the endpoints of the interval. Now, we claim that $(y-\delta,y+\delta)\subseteq (x-\epsilon,x+\epsilon)$ , and if we prove this, we are done. To prove it, let $z\in (y-\delta,y+\delta)$ , then $y-\delta$ . First, $\delta \leq y-(x-\epsilon)$ then $-\delta \geq -y+x-\epsilon$ hence $z>y-\delta \geq x-\epsilon$

On the other hand, $\delta \leq x+\epsilon-y$ then $z$ hence $z$ . Combining the inequalities, we have that $x-\epsilon$ , therefore $(y-\delta,y+\delta)\subseteq (x-\epsilon,x+\epsilon)$ as required.

3 0

3 years ago

Find the value of x..........

likoan [24]

hey do you want to talk

4 0

2 years ago

Use the relative frequency approach to estimate the probability of the event. In a certain class of students, there are 8 boys f

In-s [12.5K]

Answer:

$P\text{Student will be from Kenilworth}\approx 0.256$

Step-by-step explanation:

We have been given that that there are 8 boys from Wilmette, 5 girls from Kenilworth, 9 girls from Wilmette, 5 boys from Glencoe, 5 boys from Kenilworth and 7 girls from Glenoce.

The total number of students from Kenilworth is 5 boys plus 5 girls that is 10 students.

The total number of students in the class would be $8+5+9+5+5+7=39$

$\text{Probability}=\frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}$

$P\text{Student will be from Kenilworth}=\frac{\text{Number of student from Kenilworth}}{\text{Total number of students}}$

$P\text{Student will be from Kenilworth}=\frac{10}{39}$

$P\text{Student will be from Kenilworth}=0.2564102564$

$P\text{Student will be from Kenilworth}\approx 0.256$

Therefore, the probability, that the student will be from Kenilworth, is approximately 0.256.

7 0

3 years ago