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Elenna [48]
4 years ago
9

Write the standard form of the simplest polynomial with the roots 2, 3, and -3

Mathematics
1 answer:
koban [17]4 years ago
5 0

\text{If}\ x_1,\ x_2\ \text{and}\ x_3\ \text{are roots of a polynomial, then we can write that polynomial}\\\text{in form}\ (x-x_1)(x-x_2)(x-x_3).\\\\\text{We have\ the\ roots:}\ 2,\ 3\ \text{and}\ -3.\\\\w(x)=(x-2)(x-3)(x-(-3))=(x-2)\underbrace{(x-3)(x+3)}_{use\ a^2-b^2=(a-b)(a+b)}\\\\=(x-2)(x^2-9^2)=(x-2)(x^2-9)=(x)(x^2)+(x)(-9)+(-2)(x^2)+(-2)(-9)\\\\=x^3-9x-2x^2+18=\boxed{x^3-2x^2-9x+18}

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Answer:

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Step-by-step explanation:

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2 years ago
For a data set of the pulse rates for a sample of adult females, the lowest pulse rate is 33 beats per minute, the mean of the l
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Step-by-step explanation:

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3 years ago
Need help with all of them please, do as much as you can please!
Vlad [161]

Answer:

I believe these are all of the correct answers

1. You are correct with the 5

2. 46/3 or 15.33333

3. 84/5 or 16.8

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7. 6/15 or 0.4

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8 0
3 years ago
. A discount brokerage selected a random sample of 64 customers and reviewed the value of their accounts. The mean was $32,000 w
koban [17]

Answer:

The  90% confidence interval is  \$ \ 30313.9<  \mu  <  \$ \ 33686.13

Step-by-step explanation:

From the question we are told that

   The  sample size is  n =  64

     The sample  mean is  \= x  =  \$ 32, 000

     The  standard deviation is  \sigma=  \$ 8, 200

     

Given that the confidence interval is  90% then the level of significance is mathematically evaluated as

             \alpha  =  100 -  90

             \alpha  =  10 \%

            \alpha = 0.10

Next we obtain the critical value of  \frac{ \alpha }{2} from the normal distribution table , the value is  

       Z_{\frac{\alpha }{2} } =  1.645

  Generally the margin of error is mathematically represented as

        E =  Z_{\frac{\alpha }{2} } *  \frac{ \sigma }{ \sqrt{n} }

  =>   E =  1.645 *  \frac{  8200 }{ \sqrt{64} }

  =>   E =  1686.13

The 90% confidence interval is mathematically represented as

      \= x  -  E  <  \mu <  \= x  +  E

 =>    32000 -  1689.13 <  \mu  <  32000 +  1689.13

=>    \$ \ 30313.9<  \mu  <  \$ \ 33686.13

5 0
4 years ago
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