To solve for the time it reach the maximum height, you must solve the first derivative of the function and equate it to zero
<span>h(t) = −4.9t^2 + 14.7t + 1</span>
dh/ dt = -9.8t + 14.7
then equate to zero
-9.8t + 14.7 = 0
solve for t
t = 1.5 s
then the maximum height is when t = 1.5
<span>h(t) = −4.9t^2 + 14.7t + 1
h(1.5) = </span><span>−4.9(1.5)^2 + 14.7(1.5) + 1
h(1.5) = 12.025 m
</span>
g(x) = (1/4)x^2 . correct option C) .
<u>Step-by-step explanation:</u>
Here we have , 
and we need to find g(x) from the graph . Let's find out:
We have , . From the graph we can see that g(x) is passing through point (2,1 ) . Let's substitute this point in all of the four options !
A . g(x) = (1/4x)^2
Putting (2,1) in equation g(x) = (x/4)^2 , we get :
⇒ 
⇒ 
Hence , wrong equation !
B . g(x) = 4x^2
Putting (2,1) in equation g(x) = 4x^2 , we get :
⇒ 
⇒ 
Hence , wrong equation !
C . g(x) = (1/4)x^2
Putting (2,1) in equation g(x) = (1/4)x^2 , we get :
⇒ 
⇒ 
Hence , right equation !
D . g(x) = (1/2)x^2
Putting (2,1) in equation g(x) = (1/2)x^2 , we get :
⇒ 
⇒ 
Hence , wrong equation !
Therefore , g(x) = (1/4)x^2 . correct option C) .
Answer:
the value of x would be 108 degrees
Step-by-step explanation:
The computation of the value of x in degrees is shown below:
Given that both the triangles has the 34 degrees and 48 degrees
Now in the triangle 1 angle a = 108 degrees
And, in the triangle 2 a = x
Now in this case both the triangles are similar to each other
So here the value of x would be 108 degrees
This represent the refute the claim of Bob
Answer:
A.Put each person's name on a separate piece of paper in a bag. Randomly draw the winning name; and D.Roll a number cube. If it lands on an even number, Roddy wins. If it lands on an odd number, Scott wins.
Step-by-step explanation:
In order for it to be a fair decision, both boys have to have an equal chance of being selected.
For choice A, drawing their names from a bag, both names are equally likely to be chosen; that makes this fair.
For choice B, there is 1 way to get both heads when flipping a coin. There are 2 ways to get heads and tails when flipping a coin. This gives Scott a greater chance, so this is not fair.
For choice C, there are 2 ways to get a 1 or a 2. There are 4 ways to get anything else. This gives Scott a greater chance, so this is not fair.
For choice D, there are 3 even numbers and 3 odd numbers. Both boys have an equal chance, so this is fair.
