Yes they can! Just because two plots have the same IQR and range, does not mean that the rest of the data has to be the exact same. For example, the median.
B. x < -4
-2(3x + 6) > 4(x + 7)
-6x - 12 > 4x + 28
-10x > 40
X < -4
Answer:
C
10 x (p+2) = 30
10 x 2 = 20 30 - 20 = 10 10 ÷ 10 = 1
P = 1
10 x (1 + 2) = 30
You haven't shared "the given value of x," or, if you have, you haven't drawn attention to it.
Just suppose we were to choose x = 4 as a possible solution and then try to find a value of the parameter k that would make x = 4 an actual solution.
2(4) + 4k - 9 = (4)(4) - (4) + 1
Then 8 + 4k - 9 = 16 - 4 + 1, or 4k - 1 = 13. Then 4k = 14, and k = 14/4, or (after reduction) k = 7/2
If the parameter k equals 7/2, then x = 4 is a solution to the given equation.
To check this out further, start with the proposed solution x = 5 and find k.
An inequality for the poroblem is 2000 - 637 and to turn that into algebraic expression it would be 2000 - 637 = 1363
