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Sin^(1/2) x cos x - sin^(5/2) cos x
= sin^(1/2) x cos x - sin(1/2)x sin^2 x cos x
factoring we get:
cos x sin^(1/2) x ( 1 - sin^2 x)
Now 1 - sin^2 x = cos^2 x so we have
cos x sin^(1/2) x * cos^2 x
= cos^3 x sqrt sin x
One way:
585-320=265 (Rounding to the nearest 5)
590-320=270 (Rounding to the nearest 10)
600- 300= 300 (Rounding to the nearest 100)
Hope you found this helpful :)
Answer:
And the width for the confidence interval is given by:
And we want to see the effect if we increase the confidence level for a interval. On this case if we increase the confidence level then the critical value for the confidence interval 
would be higher and then the width of the interval would increase. So then the best answer for this case would be:
B. Increasing the level of confidence widens the interval.
Step-by-step explanation:
Let's assume that we have a parameter of interest 
who represent for example the true mean for a population. And we can construct a confidence interval in order to estimate this parameter if we know the distribution for the statistic let's say 
and for this particular example the confidence interval is given by:
Where ME represent the margin of error for the estimation and this margin of error is given by:
And the width for the confidence interval is given by:
And we want to see the effect if we increase the confidence level for a interval. On this case if we increase the confidence level then the critical value for the confidence interval would be higher and then the width of the interval would increase. So then the best answer for this case would be:
B. Increasing the level of confidence widens the interval.
< because a negative is less than a positive
