Three-fourths of the employees at a bookstore came to a staff meeting. Less than 24 employees were at the meeting. The inequalit
y representing this scenario is 3/4 e < 24, where e represents the total number of employees. Which graph shows the solution to the inequality?
2 answers:
Answer:
The correct option is 4.
Step-by-step explanation:
It is given that the three-fourths of the employees at a bookstore came to a staff meeting. Less than 24 employees were at the meeting.
Let the total number employees be e.
Three fourth of the total employees is , the total number of employees at the meeting were less than 24.
Multiply 4 both sides.
Divide both sides by 3.
Therefore the value of e is less than 32.
In a number line as we approach towards left the the value of integers decreases.
Since the value of e is less than 32, therefore the solution graph is from negative infinity to 32.
Since 32 is not included in the solution set, therefore there is an open circle on 32.
Option 4 is correct.
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Answer:
Larger rocket: 36 kiloliters
smaller rocket: 24 kiloliters
Step-by-step explanation:
Lets assign the letters: "L" to the number of kiloliters the "Larger" rocket gets, and "S" to the number of kiloliters that the "Smaller" rocket gets.
We can create two equations from the words given in the problem:
First equation: <em>A total of 60 kiloliters is to be used for "L" plus "S"</em>:
which gives us:
Next equation comes from the words: "<em>The smaller rocket receives 12 kiloliters less than the larger rocket</em>"
which gives us:
Now we can use this last equation to replace for the "S" unknown in the first equation (and thus reducing the problem to one equation with one unknown (L), that one can easily solve):
Therefore the amount of fuel that the larger rocket gets is 36 kiloliters.
And using the equation "S = L - 12" we get:
Which tells us that the smaller rocket gets 24 kiloliters of fuel.
Area of the electronic board is 9000 cm2
Step-by-step explanation:
Write ratios to represent the unknown actual length and width of the display to the scale length and width of the display.
The Electronic board always seems like a rectangular shape
Length= scale÷Actual = 5/36 = 5×36 = 180cm
Width=scale÷Actual = 1/50 = 1×50 = 50cm
Area of Rectangle = legnth × width
= 180cm × 50cm = 9000 cm2
Area of the electronic board is 9000 cm2