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yan [13]
3 years ago
7

How do i convert mixed frations into improper fractions\

Mathematics
2 answers:
Ainat [17]3 years ago
3 0

Answer:

how to convert

Step-by-step explanation:

To convert a mixed number to an improper fraction, follow these steps: Multiply the denominator of the fractional part by the whole number, and add the result to the numerator. Use this result as your numerator, and place it over the denominator you already have. This method works for all mixed numbers

KengaRu [80]3 years ago
3 0

Answer:

Change the whole numbers

Step-by-step explanation:

For example

5 3/6

A whole number written as a fraction for this problem is 6/6.

If the problem was 7 4/9, it would 9/9

I'd the problem was 2 3/4, it would be 4/4.

So basically a whole number written as a fraction is when both the top and bottom number are the same. when divide by each other they equal one. 6 divided by 6 is 1, 9 divided by 9 is 1, 4 divide by 4 is 1.

First

Turn 5 3/6 into 5/1 + 3/6

Now add them to together

To add fractions together they have to have the same denominator or bottom number.

What is a number 1 and 6 have in common ?

6 because 1 can be multiplied with any number but 6 can never be multiplied to create 1.

5 is simple 5 whole numbers

so 5/1 × 6/6= 30/6

30/6 + 3/6 = 33/6

now it's an improper faction. There is no whole number, it been converted into a fraction where the top is bigger than the bottom hence why it is improper

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Solve the system by using the inverse of the coefficient matrix. -3x + 9y = 9 3x + 2y = 13 Group of answer choices
kirill [66]

Answer:

x= 3

y=2

Step-by-step explanation:

-3x + 9y = 9 ----------- equation 1

3x + 2y = 13--------------- equation 2

In  Matrix Form                            

\left[\begin{array}{cc}-3&9\\3&2\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right] = \left[\begin{array}{c}9\\13\end{array}\right]                  

Let A = \left[\begin{array}{cc}-3&9\\3&2\end{array}\right]    X =  \left[\begin{array}{c}x\\y\end{array}\right]  and B =    \left[\begin{array}{c}9\\13\end{array}\right]  

Then Mathematically AX= B

or X= A⁻¹ B

Where A⁻¹ = Adjacent A/ mod of A

Adjacent A =   \left[\begin{array}{cc}2&-9\\-3&-3\end{array}\right]    

Mod Of A= -6 - (27) = -33 which is not equal to zero

so Putting These values in the given formula

X= 1/-33    \left[\begin{array}{cc}2&-9\\-3&-3\end{array}\right]      \left[\begin{array}{c}9\\13\end{array}\right]  

Now Multiplying Rows and Columns

   \left[\begin{array}{c}x\\y\end{array}\right] = -1/33    \left[\begin{array}{cc}2*9+- 9*13\\-3*9 +- 3*13\end{array}\right]

Solving the Matrix we get

  \left[\begin{array}{c}x\\y\end{array}\right] = -1/33  \left[\begin{array}{cc}18-117\\-27-39\\\end{array}\right]

  \left[\begin{array}{c}x\\y\end{array}\right] = -1/33  \left[\begin{array}{cc}-99\\-66\end{array}\right]

From Here we find x= 99/33 or 3

and y = 66/33= 2

4 0
3 years ago
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