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aksik [14]
3 years ago
9

There are 12 donuts in one dozen donuts. Which equation could be used to find the total (T) number of donuts (d) in 6 dozen?

Mathematics
1 answer:
Lady_Fox [76]3 years ago
3 0

Answer:d*6=t

Step-by-step explanation:

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3.
Law Incorporation [45]

Answer:

5 m

Step-by-step explanation:

Use the volume formula, V = lwh

Plug in the volume, width, and height, then solve for l (the length)

V = lwh

70 = (l)(2)(7)

70 = 14l

5 = l

So, the length of the rectangular prism is 5 m

6 0
3 years ago
Read 2 more answers
W^2-49=0 what are both solutions one is what's the other??
Alborosie
W² - 49 = 0
w² - 7² = - 
(w-7)(w+7)=0
w -7=0 , or w + 7 =0
w=-7, w=7

Answer: -7, 7.
3 0
3 years ago
A woman invests 12,500 in a savings account drawling interest that is compounded annually. Find the annual rate if the money gro
Anuta_ua [19.1K]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill &\$14045\\ P=\textit{original amount deposited}\dotfill &\$12500\\ r=rate\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases}

\bf 14045=12500\left(1+\frac{r}{1}\right)^{1\cdot 2}\implies \cfrac{14045}{12500}=(1+r)^2\implies \cfrac{2809}{2500}=(1+r)^2 \\\\\\ \sqrt{\cfrac{2809}{2500}}=1+r\implies \cfrac{53}{50}=1+r\implies \cfrac{53}{50}-1=r\implies \cfrac{3}{50}=r \\\\\\ 0.06=r\implies \stackrel{\textit{converting it to percent format}}{0.06\cdot 100=r}\implies \stackrel{\%}{6}=r

4 0
3 years ago
Read 2 more answers
Find the absolute maximum and minimum values of f(x.y)=x^2+y^2-2x-2y on the closed region bounded by the triangle with vertices
dem82 [27]

Try this suggested solution, note, 'D' means the region bounded by the triangle according to the condition. It consists of 6 steps.

Answers are underlined with red colour.

6 0
3 years ago
See Attached picture.
agasfer [191]
We use the Work formula to solve for the unknown in the problem which is W = F x d. First, we solve for the Net Force acting on the car. The Net Force is the summation of all forces acting on the object. For this case, we assume that Friction Force is negligible thus the Net Force is equal to:

F = mgsinα in terms of SI units and in terms of english units we have F = m(g/g₀)(sin α) where g₀ is the proportionality factor, 32.174 ft lb-m / lb-f s²

F = 2500 (32.174/32.174) (sin 12°) = 519.78 lb

W = Fd = 519.78 lb (400 ft) = 207912 ft - lb or 20800 ft-lb
5 0
3 years ago
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