Answer:
b) -10 m/s
Explanation:
In perfectly elastic head on collisions of identical masses, the velocities are exchanged with one another.
The acceleration of the box is approximately 
Explanation:
According to Newton's second law of motion, the net force acting on the box is equal to the product between its mass and its acceleration:
where
is the net force
m = 12.0 kg is the mass of the box
a is the acceleration
The net force can be written as
where
is the applied forward force
is the friction force
Combining the two equations,
And solving for the acceleration,
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Answer:
B. equals zero
Explanation:
Given data
one complete cycle = heat flow
solution
we have given that when heat engine complete 1 cycle change in energy = net heat flow
that is always equal to zero
from first law of thermodynamics that
ΔU = Q + W
we know ΔU is the change internal energy in system and Q is net heat transfer in system and W is net work done in system
therefore change of internal energy during one cycle
ΔU = Ufinal - Uinitial
ΔU = Uinitial - Uinitial = 0
|Acceleration| = (change in speed) / (time for the change).
Change in speed = (6 mi/hr - 25 mi/hr) = -19 mi/hr
Time for the change = 10 sec
|Acceleration| = (-19 mi/hr) / (10 sec) = -1.9 mile per hour per second
Admittedly, that's a rather weird unit.
Other units, perhaps more comfortable ones, are:
-6,840 mi/hr²
-2.79 feet/sec²
Answer:
A) d = 11.8m
B) d = 4.293 m
Explanation:
A) We are told that the angle of incidence;θ_i = 70°.
Now, if refraction doesn't occur, the angle of the light continues to be 70° in the water relative to the normal. Thus;
tan 70° = d/4.3m
Where d is the distance from point B at which the laser beam would strike the lakebottom.
So,d = 4.3*tan70
d = 11.8m
B) Since the light is moving from air (n1=1.00) to water (n2=1.33), we can use Snell's law to find the angle of refraction(θ_r)
So,
n1*sinθ_i = n2*sinθ_r
Thus; sinθ_r = (n1*sinθ_i)/n2
sinθ_r = (1 * sin70)/1.33
sinθ_r = 0.7065
θ_r = sin^(-1)0.7065
θ_r = 44.95°
Thus; xonsidering refraction, distance from point B at which the laser beam strikes the lake-bottom is calculated from;
d = 4.3 tan44.95
d = 4.293 m
