Answer:
9:00 AM
Explanation:
I took the test and that was the answer
Answer:
Explanation:
Given
Resistor A has length ![L_1](https://tex.z-dn.net/?f=L_1)
and Resistor B has Length ![L_2](https://tex.z-dn.net/?f=L_2)
and Resistance is given by
![R=\frac{\rho L}{A}](https://tex.z-dn.net/?f=R%3D%5Cfrac%7B%5Crho%20L%7D%7BA%7D)
Considering
and A to be constant thus
because ![L_2>L_1](https://tex.z-dn.net/?f=L_2%3EL_1)
(a)When they are connected in series
As the current in series is same and power is ![i^2R](https://tex.z-dn.net/?f=i%5E2R)
therefore
as R is greater for second resistor
(b)if they are connected in Parallel
In Parallel connection Voltage is same
![P=\frac{V^2}{R}](https://tex.z-dn.net/?f=P%3D%5Cfrac%7BV%5E2%7D%7BR%7D)
resistance of 2 is greater than 1 thus Power delivered by 1 is greater than 2
Yah isnt that obvious? Gasses mix everywhere in all proportions.
<h3>
Answer:</h3>
<h3>
Explanation:</h3>
_______________
λ=500 nm = 500·10⁻⁹ m
c=3·10⁸ m/s
h=6,63·10⁻³⁴ J·s = 4,14·10⁻¹⁵ eV·s
_______________
E - ?
_______________
![\displaystyle \boldsymbol{E}=h\nu =h \frac{c}{\lambda} =4,14\cdot 10^{-15} \; eV\cdot s\cdot \; \frac{3\cdot 10^8\; m/s}{500\cdot 10^{-9}\; m} =2,484\; eV\approx \boldsymbol{2,5\; eV}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cboldsymbol%7BE%7D%3Dh%5Cnu%20%3Dh%20%5Cfrac%7Bc%7D%7B%5Clambda%7D%20%3D4%2C14%5Ccdot%2010%5E%7B-15%7D%20%5C%3B%20eV%5Ccdot%20s%5Ccdot%20%5C%3B%20%5Cfrac%7B3%5Ccdot%2010%5E8%5C%3B%20m%2Fs%7D%7B500%5Ccdot%2010%5E%7B-9%7D%5C%3B%20m%7D%20%3D2%2C484%5C%3B%20%20eV%5Capprox%20%5Cboldsymbol%7B2%2C5%5C%3B%20eV%7D)