The teacher measured the maximum height and the minimum height of ...
5 days ago — ... screen as the wave passed . The teacher repeated his measurements. Table 4 shows the teacher's measurements. Calculate the mean amplitude of the water wave.
If you stand on one side of a strike-slip fault and the block on the other side of the fault has moved to your left, this is known as a(n) left lateral fault.
There are several distinct sorts of fault lines, and they are called based on the fault's movement and the fault plane's own direction. These faults may be found all over the world, but the most active and earthquake-producing ones are in the Pacific Ocean's Ring of Fire region.
When you gaze along the length of a fault line, the left side will move toward you while the right side moves away from you. This is referred to as a left-lateral fault.
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Answer:
a) 
b) 
c) 
d) 
e) 
Explanation:
a) Let's recall the definition of work.
Because the system is a quasi-static isobaric expansion, P is constant here, therefore:
![W=2.0\cdot 10^{5}(4.0\cdot 10^{-3}-2.0\cdot 10^{-3})= 400 [Nm^{2}]](https://tex.z-dn.net/?f=W%3D2.0%5Ccdot%2010%5E%7B5%7D%284.0%5Ccdot%2010%5E%7B-3%7D-2.0%5Ccdot%2010%5E%7B-3%7D%29%3D%20400%20%5BNm%5E%7B2%7D%5D)
b) Using the ideal gas equation we have:
(1)
and 
(2)
We can note that n times R is a constant in (1) and (2), so we can equal those equations.
(3)
Let's solve T₂ for (3), let's recall that P₁ = P₂, so they canceled out
c) Using the equation of ideal gas we have:
d) We can write the internal energy as a function of Cv, and as we know the Cv is 1.5R for a monoatomic gas.
e) Using the first law of thermodynamic, we have:
Finally,
Have a nice day!
Answer:
135J
Explanation:
So we know ΔKinetic Energy= ΔWork
Kinetic energy=1/2mv²
So Kf-Ki=ΔK
ΔK=1/2*0.45(25²-5²)=135J
135J=ΔWork
