2 years ago

The table shows the diameters of the planets in our solar system. Assume that a basketball whose diameter is 25

Physics

1 answer:

tino4ka555 [31]2 years ago

3 0

Answer:

Mercury:

.85

pea

Venus:

2.1

gumball

Earth:

2.2

gumball

Mars:

1.2

marble

Uranus:

grapefruit

Neptune:

8.6

softball

Explanation:

I have no clue if I'm right but hopefully, I am

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Which of the following is true? A. If an equal force is applied to two objects, the object with greater mass will accelerate mor

docker41 [41]

B

I hope this helps and have a wonderful day filled with joy!!

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4 0

3 years ago

Two point charges are brought closer together, increasing the force between them by a factor of 17. By what factor was their sep

nignag [31]

Answer:

$\dfrac{r_1}{r_2}=4.123$

Explanation:

Given:

Final force between them=17(initial force between them)

initial separation between them $r_1$

Final separation between them $r_2$

Let Q and q be the charges on them then

$F_2=17F_1\\\dfrac{kQq}{r_2^2}=17\dfrac{kQq}{r_1^2}\\\dfrac{r_1^2}{r_2^2}=17\\\dfrac{r_1}{r_2}=4.123$

6 0

3 years ago

Why do scientist use different types of models to represent compounds

nexus9112 [7]

Because they are different they all show different traits.

5 0

3 years ago

Determine the inductance L of a 0.65-m-long air-filled solenoid 3.2 cm in diameter containing 8400 loops.

den301095 [7]

Answer:

The inductance is $L = 0.1097 \ H$

Explanation:

From the question we are told that

The length is $l = 0.65 \ m$

The diameter is $d = 3.2 cm = 0.032 \ m$

The number of loops is $N = 8400$

Generally the radius is evaluated as

$r = \frac{ 0.032 }{2} = 0.016 \ m$

The inductance is mathematically represented as

$L = \frac{ \mu_o * N^2 * A }{ l }$

Here $\mu_o$ is the permeability of free space with value $\mu_o = 4\pi * 10^{-7} N/A^2$

A is the cross-sectional area which is mathematically evaluated as

$A = \pi r^2$

=> $A = 3.142 * (0.016)^2$

=> $A = 0.000804 \ m^2$

=> $L = \frac{ 4\pi * 10^{-7} * 8400^2 * 0.000804 }{ 0.65 }$

=> $L = 0.1097 \ H$

5 0

3 years ago

A constant force of 10 N is applied to an object. The object accelerates at a constant rate of 4 m/s2. What is the mass of the o

tatuchka [14]

Answer:

I think it is 2.5 kg.

Explanation:

I can say you do:

Fnet = m * a

So, you want to find mass:

m = Fnet / a

So, the answer you will receive is 2.5

7 0

3 years ago