15x 9.8 x .3 = 44.1
15 x 9.8 x 1 = 147
147 - 44.1 = 102.9J
102.9 J
Velocity = Frequency x Wavelength
= 18 x 13 = 234 mm/s
50 *15=750
work is force time distance times angle between both vectors
here the angle is 0.
Answer:
The magnitude of the acceleration is 4.2 m/s²
Explanation:
Given;
initial velocity of the powerful sports car, u = 0
final velocity of the powerful sports car, v = 25 m/s
time of motion, t = 6 seconds
Acceleration = Δv / Δt
Δv is change in velocity
Δt is change in time
The magnitude of the acceleration of the powerful sports car during the motion is given by;

Therefore, the magnitude of the acceleration is 4.2 m/s²
A car slowing as it reaches a traffic light, because it is the only option with acceleration/ deceleration.
And forces require the mass of the object AND the acceleration.