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dexar [7]
3 years ago
8

A bin contains three components from supplier a, four from supplier b, and five from supplier

Mathematics
1 answer:
TEA [102]3 years ago
4 0
<span>The number of ways to select one component from each supplier is 3*4*5 since you can choose one of three from A, in each case you can then choose 1 of 4 from B and lastly for each selection from A and B you have 5 possible choices for C. After that you have 12-3=9 components left for choice of the fourth component to test. Thus there will be 3*4*5*9 different ways to choose at least one from each supplier.</span>
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Best known for its testing program, ACT, Inc., also compiles data on a variety of issues in education. In 2004 the company repor
GarryVolchara [31]

Answer:

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

Step-by-step explanation:

Check for conditions

For this case in order to use the normal distribution for this case or the 68-95-99.7% rule we need to satisfy 3 conditions:

a) Independence : we assume that the random sample of 400 students each student is independent from the other.

b) 10% condition: We assume that the sample size on this case 400 is less than 10% of the real population size.

c) np= 400*0.74= 296>10

n(1-p) = 400*(1-0.74)=104>10

So then we have all the conditions satisfied.

Solution to the problem

For this case we know that the distribution for the population proportion is given by:

p \sim N(p, \sqrt{\frac{p(1-p)}{n}})

So then:

\mu_p = 0.74

\sigma_p =\sqrt{\frac{0.74(1-0.74)}{400}}=0.0219

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

5 0
3 years ago
4x + 1/3 y 2 what is the value of the expression above when x = 2 and y = 3
GenaCL600 [577]
Hoi!

To solve this, first plug in the values for x and y.

x = 2, so anywhere you see x, put 2 in its place.

y = 3, so anywhere you see y, put 3 in its place.

4(2) +  \frac{1}{2}(3)

4 × 2 = 8

\frac{1}{2} × 3 = 1 \frac{1}{2}


8 +1 \frac{1}{2} = 9 \frac{1}{2}

9 \frac{1}{2} is your answer.



4 0
2 years ago
Read 2 more answers
Of the employees who work at Stalling Printing, 90% attended the safety procedures meeting. If 63 employees attended the meeting
LUCKY_DIMON [66]
There are 70 employees who work at Stalling Printing.

Take note that the 63 employees who attended the meeting represents 90% of the total number of employees working at Stalling Printing. To get the total number of employees or the 100% number of employees, divide 63 by its percentage, 90%.

63/90% or 63 / 0.90 = 70 total number of employees.

Out of 70 employees; 63 employees attended the meeting and 7 employees did not.

4 0
3 years ago
(x - 4/6) = (x + 2/12) what is x please show your work.
Sergio039 [100]
The equation has no solution
4 0
3 years ago
Please help soon! Thanks! Solve for x
EastWind [94]

Answer:

x=30^{\circ}

Step-by-step explanation:

Looking at \triangle LMN:

\angle NML = 180 - (90+45) (angle sum of triangle is 180^{\circ})

=45^{\circ}

Looking at \triangle KNM:

\angle KNM = 180-105 (angle of straight is 180^{\circ})

=75^{\circ}

\angle KNM + \angle NKM + \angle KMN = 180 (angle sum of triangle is 180^{\circ)

75+2x+45 = 180

2x+120 = 180

2x=60

x=30^{\circ}

Hope this helps :)

8 0
2 years ago
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