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3 years ago

A bin contains three components from supplier a, four from supplier b, and five from supplier

1 answer:

4 0

The number of ways to select one component from each supplier is 3*4*5 since you can choose one of three from A, in each case you can then choose 1 of 4 from B and lastly for each selection from A and B you have 5 possible choices for C. After that you have 12-3=9 components left for choice of the fourth component to test. Thus there will be 3*4*5*9 different ways to choose at least one from each supplier.

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Order 1.62, 16.2%, 15/20 from greatest to least

N76 [4]

1.62, 15/20, 16.2% is the answer

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2 years ago

Read 2 more answers

A pool in the shape of a rectangle prism is being filled with water. The length and width is 24 feet and 15 feet. If the hight o

hram777 [196]

Check the picture below.

$\textit{volume of a rectangular prism}\\\\ V=Lwh~~ \begin{cases} L=length\\ w=width\\ h=height\\[-0.5em] \hrulefill\\ L=24\\ w=15\\ h=1\frac{1}{3} \end{cases}\implies V=(24)(15)(1\frac{1}{3})\implies \stackrel{in~ft^3}{V}=(24)(15)(\frac{4}{3}) \\\\\\ \stackrel{\textit{converting all feet to inches}}{\stackrel{in~in^3}{V}=(24\cdot 12)(15\cdot 12)(\frac{4}{3}\cdot 12)}\implies V=(288)(180)(16)\implies V=\stackrel{in^3}{829440}$

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2 years ago

You are studying the relationship between the history of early childhood trauma (categorized as trauma/no trauma) and weight in

jeka57 [31]

Answer:

You can decide to reject the Null Hypothesis at p < 0.05.

Step-by-step explanation:

In this case, the relationship between the history of early childhood trauma and weight in adulthood are being studied.

The categories of childhood trauma are:

Trauma and No trauma.

So, number of rows is, r = 2.

The categories of weight in adulthood are:

Low to normal, Overweight, and Obese

So, number of columns is, c = 3.

The distribution of the statistic $\chi^{2}$ is chi-square with (r - 1)(c - 1) degrees of freedom, where r represents the number of rows in the two-way table and c represents the number of columns.

Compute the degrees of freedom as follows:

$df = (r-1)(c-1)=(2-1) \times (3-1) = 2$

It is provided that the calculated value of Chi-square test statistic is 18.26.

Compute the p-value of the test as follows:

$p-value=P(\chi^{2}_{2}\geq 18.26)\\=0.000108\\\approx0.00011$

Decision rule:

The null hypothesis will be rejected if the p-value of the test is less than the significance level.

The significance level is, α = 0.05.

p-value = 0.00011 < α = 0.05.

The null hypothesis will be rejected at 5% level of significance.

Thus, the complete statement is:

"You can decide to reject the Null Hypothesis at p < 0.05."

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3 years ago

Maggie and her sister bought for their mother that gift of $54.75. maggie contributed $26 to the gift. write an addition equatio

natita [175]

Answer:

54.75 = 26 + x

Step-by-step explanation:

You can solve for x by subtracting 26 from both sides of the equation.

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3 years ago

Check all of the proper units of weight in the metric system.

MissTica

Gram and milligram are in the metric system and are for weight. Pound is the United States system and kiloliter measures liquids

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3 years ago