A bin contains three components from supplier a, four from supplier b, and five from supplier

1 answer:

4 0

<span>The number of ways to select one component from each supplier is 3*4*5 since you can choose one of three from A, in each case you can then choose 1 of 4 from B and lastly for each selection from A and B you have 5 possible choices for C. After that you have 12-3=9 components left for choice of the fourth component to test. Thus there will be 3*4*5*9 different ways to choose at least one from each supplier.</span>

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Assume that the function call operator() is overloaded for data type String in the usual sense of selecting a substring from a l

krek1111 [17]

Answer:

"EF"

Step-by-step explanation:

Given

String1 = "ABCDEFGHI"

Substring : String1(4,2)

To solve this, one must understand the following

1. The function call operator () is used to overload objects of class type.

2. A copy constructor must receive its argument by reference to prevent an otherwise infinite recursion.

3. overload ( ), doesn't mean that one is not creating a new way to call a function; instead, it is a way to create an operator function that can be passed an arbitrary number of parameters

Having pointed out this,

The string to overload goes thus

String1 = "ABCDEFGHI"

The parameters goes thus

String1(4,2)

To represent this properly, we have

("ABCDEFGHI",4,2)

Which means to return 2 strings starting from the 4th index character.

It should be noted that index starts at 0.

So, the character at the 4th index is "E"

Then, we count 2 characters starting from E (i.e. E, inclusive)

This gives