All categories

4 years ago

____________________ when objects collide, the total initial momentum equals the total final momentum

Physics

2 answers:

Karo-lina-s [1.5K]4 years ago

8 0

Its called law of conservation momentum

Alexus [3.1K]4 years ago

7 0

The law of conservation of linear momentum says that when objects collide, the total initial momentum equals the total final momentum.
The momentum of a body is given by the product of mass and velocity of the object.

You might be interested in

A helicopter (m = 3250 kg) is cruising at a speed of 56.9 m/s atan altitude of 185 m. What is the total mechanical energy of the

taurus [48]

Answer:

The mechanical energy of the helicopter is $1.12\times 10^7\ J$ .

Explanation:

It is given that,

Mass of the helicopter, m = 3250 kg

Speed of the helicopter, v = 56.9 m/s

Position of the helicopter, h = 185 m

The energy possessed by an object due to its motion is called its kinetic energy. It is given by :

$E=\dfrac{1}{2}mv^2$

$E=\dfrac{1}{2}\times 3250\times (56.9)^2$

$E=5.26\times 10^6\ J$

The energy possessed by an object due to its position is called its potential energy. It is given by :

$E=mgh$

$E=3250\times 9.8\times 185$

$E=5.89\times 10^6\ J$

The sum of kinetic and potential energy is called mechanical energy of the system. It is given by :

$M=5.26\times 10^6+5.89\times 10^6$

$M=11.15\times 10^6\ J$

$M=1.12\times 10^7\ J$

So, the mechanical energy of the helicopter is $1.12\times 10^7\ J$ . Hence, this is the required solution.

6 0

3 years ago

Verify that for values of n less than 8, the system goes to a stable equilibrium, but as n passes 8, the equilibrium point becom

irakobra [83]

Answer:

Biological system is one of the major causes of oscillation due to sensitive negative feedback loops. For instance, imagine a father teaching his son how to drive, the teen is trying to keep the car in the centre lane and his father tell him to go right or go left as the case may be. This is a example of a negative feedback loop of a biological system. If the father's sensitivity to the car's position on the road is reasonable, the car will travel in a fairly straight line down the centre of the road. On the other hand, what happens if the father raise his voice at the son "go right" or when the car drifts a bit to the left? The startled the son will over correct, taking the car too far to the right. The father will then starts yelling "go left" then the boy will over correct again and the car will definitely oscillate back and forth. A scenario that indicates the behavior of a car driver under a very steep feedback control mechanism. Since the driver over corrects in each direction. Therefore causes oscillations.

Explanation:

5 0

3 years ago

A record turntable is rotating at 33 rev/min. A watermelon seed is on the turntable 4.0 cm from the axis of rotation. (a) Calcul

Annette [7]

Answer:

a) a = 0.477 m/s^2

b) u = 0.04862

Explanation:

Given:-

- The rotational speed of the turntable N = 33 rev/min

- The watermelon seed is r = 4.0 cm away from axis of rotation.

Find:-

(a) Calculate the acceleration of the seed, assuming that it does not slip. (b) What is the minimum value of the coefficient of static friction between the seed and the turntable if the seed is not to slip

Solution:-

- First determine the angular speed (w) of the turntable.

w = 2π*N / 60

w = 2π*33 / 60

w = 3.456 rad/s

- The watermelon seed undergoes a centripetal acceleration ( α ) defined by:

α = w^2 * r

α = 3.456^2 * 0.04

α = 0.477 m / s^2

- The minimum friction force (Ff) is proportional to the contact force of the seed.

- The weight (W) of the seed with mass m acts downwards. The contact force (N) can be determined from static condition of seed in vertical direction.

N - W = 0

N = W = m*g

- The friction force of the (Ff) is directed towards the center of axis of rotation, while the centripetal force acts in opposite direction. The frictional force Ff = u*N = u*m*g must be enough to match the centripetal force exerted by the turntable on the seed.

Ff = m*a

u*m*g = m*a

u = a / g

u = 0.477 / 9.81

u = 0.04862

8 0

3 years ago

A man drags a 71-kg crate across the floor at a constant velocity by pulling on a strap attached to the bottom of the crate. The

Flura [38]

Answer:

T = 540 N (to two significant digits)

Explanation:

Let the crate dimension L be from strap attachment to floor contact

Let T be the strap tension

sum moments about the floor contact point to zero

mg[½Lcos25] - Tsin61[Lcos25] + Tcos61[Lsin25] = 0

L is common to all terms, so divides out.

½(71)(9.8)cos25 = T(sin61cos25 - cos61sin25)

T = (71)(9.8)cos25 / (2(sin61cos25 - cos61sin25))

T = 536.428020...

7 0

3 years ago

compared to an object that does not roll, but instead slides without friction, should a rolling object be released from the same

Zinaida [17]

Answer:

from a lesser hight

Explanation:

because you need less force

hope its right if it is mark brainlyest ;)

6 0

2 years ago