A horizontal force of 92.7 N is applied to a 40.5 kg crate on a rough, level surface. If the crate accelerates at 1.13 m/s2, wha
1 answer:
Answer:
The value is
Explanation:
From the question we are told that
The magnitude of the horizontal force is
The mass of the crate is
The acceleration of the crate is
Generally the net force acting on the crate is mathematically represented as
Here is force of kinetic friction (in N) acting on the crate
So
=>
You might be interested in
Answer:
Secondary voltage on second transformer is 200 volt.
Explanation:
It is given two transformer
Let us consider first transformer.
Number of turns in primary
Numb er of turns in secondary
Now consider second transformer
Number of turns in primary
Number of turns in secondary
Now it is given that same voltage of 50 volt is applied to primary of both the transformer.
For second transformer
So secondary voltage on second transformer is 200 volt
Answer:
Distance, d = 61.13 ft
Explanation:
It is given that,
Initial speed of the car, u = 50 mi/h = 73.34 ft/s
Finally, it stops i.e. v = 0
Deceleration of the car,
We need to find the distance covered before the car comes to a stop. Let the distance is s. It can be calculated using third law of motion as :
s = 61.13 ft
So, the distance covered by the car before it comes to rest is 61.13 ft. Hence, this is the required solution.