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2 years ago

6

The solutions to x2-5x-14=0 are what

2 answers:

Anvisha [2.4K]2 years ago

8 0

Answer:

-2

Step-by-step explanation:

vlabodo [156]2 years ago

8 0

The solutions to x2-5x-14=0 is -2

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What is the value for k?<br><br> 1/2k + 6 = 4k - 8<br><br> a.) -4<br> b.) -3<br> c.) 3<br> d.) 4

inessss [21]

I hope this helps you

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3 years ago

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Dovator [93]

Answer:

g= - 3x/x-2

Step-by-step explanation:

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2 years ago

Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers.

Levart [38]

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is $Q(x,y)$ is predicate that $x$ then $x^{2}$ . where $x,y$ are rational numbers.

a)

when $x=-2, y=1$

Here $-2$ that is $x$ satisfied. Then

$(-2)^{2}$

$4$ this is wrong. since $4>1$

That is $x^{2}$ $>y^{2}$ Thus $Q(x,y)$ $=Q(-2,1)$ is false.

b)

Assume $Q(x,y)=Q(-5,2)$ .

That is $x=-5, y=2$

Here $-5$ that is $x$ this condition is satisfied.

Then

$(-5)^{2}$

$25$ this is not true. since $25>4$ .

This is similar to the truth value of part (a).

Since in both $x$ satisfied and $x^{2} >y^{2}$ for both the points.

c)

if $Q(x,y)=Q(3,8)$ that is $x=3$ and $y=8$

Here $3$ this satisfies the condition $x$ .

Then $3^{2}$

$9$ This also satisfies the condition $x^{2}$ .

Hence $Q(3,8)$ exists and it is true.

d)

Assume $Q(x,y)=Q(9,10)$

Here $9$ satisfies the condition $x$

Then $9^{2}$

$81$ satisfies the condition $x^{2}$ .

Thus, $Q(9,10)$ point exists and it is true. This satisfies the same values as in part (c)

6 0

3 years ago

Someone plz help me :(

irina [24]

Answer: 5 : 12

Step-by-step explanation:

the total flower = 5 + 7 = 12

so tulips to total flowers = 5 : 12

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2 years ago

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What is 7.75 in word form?

iris [78.8K]

Seven and Seventy-Five Hundredths

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3 years ago

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