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3 years ago

14

In circle V, angle WXZ measures 30°. Line segments WV,

2 answers:

-BARSIC- [3]3 years ago

7 0

Answer:

C

Step-by-step explanation:

PtichkaEL [24]3 years ago

6 0

Answer:

120 On edge i got it right

Step-by-step explanation:

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Six more than the quotient of a number be in 30 is greater than three

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Answer:

heheheheggfjdydvgeh hi jgeuhyuhf

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3 years ago

Read 2 more answers

Compare taking a cube root to taking a square root

blsea [12.9K]

The cube root of a number is the number which when multiplied by itself three times give you the original number. ... The square root of a number is the number which when multiplied by itself twice give you the original number. As an example, the square root of 9 is 3 because 3×3 = 9

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4 years ago

Write a problem that involves finding the unknown measure of a side of a rectangle include the solution?

tankabanditka [31]

Problem:
The area of the patio of a relative's house is 20 square meters.
The width of the patio is 2 meters.
What is the length of the patio?
Solution:
The area is:
A = (w) * (l)
Where,
w: width
l: long
Clearing l we have:
l = A / w
Substituting values:
l = 20/2
l = 10 meters

7 0

3 years ago

In a continuous series, mean(x) = 80, assumed mean(A) = 60 and<br>EF=40 then find the value of EFd.

Aneli [31]

Using the given information, the value of Σfd is 800

<h3>Calculating mean using Assumed mean </h3>

From the question, we are to determine the value of Σfd

The formula for mean, using the assumed mean method is given by

$\bar x = A + \frac{\sum fd}{\sum f}$

Where $\bar x$ is the mean

A is the assumed mean

From the given information,

$\bar x = 80$

$A = 60$

$\sum f = 40$

Putting the parameters into the equation, we get

$80 = 60 + \frac{\sum fd}{40}$

$80-60 = \frac{\sum fd}{40}$

$20 = \frac{\sum fd}{40}$

$\sum fd = 20 \times 40$

$\sum fd = 800$

Hence, the value of Σfd is 800

Learn more on Mean here: brainly.com/question/20118982

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8 0

2 years ago

Rewrite as y−k=a(x−h)2 or x−h=a(y−k)2. Find the vertex, focus, and directrix.<br> y−3=(2−x)^2

Talja [164]

Given:

The given equation is

$y-3=(2-x)^2$

To find:

The vertex, focus, and directrix.

Solution:

The equation of a parabola is

$y-k=a(x-h)^2$ ...(i)

where, (h,k) is vertex, $\left(h,k+\dfrac{1}{4a}\right)$ and directrix is $y=k-\dfrac{1}{4a}$

We have,

$y-3=(2-x)^2$

It can be written as

$y-3=(-(x-2))^2$

$y-3=(x-2)^2$ ...(ii)

On comparing (i) and (ii), we get

$h=2,k=3,a=1$

Vertex of the parabola is (2,3).

$Focus=\left(2,3+\dfrac{1}{4(1)}\right)$

$Focus=\left(2,3+\dfrac{1}{4}\right)$

$Focus=\left(2,\dfrac{13}{4}\right)$

Therefore, the focus of the parabola is $\left(2,\dfrac{13}{4}\right)$ .

Directrix of the parabola is

$y=3-\dfrac{1}{4(1)}$

$y=3-\dfrac{1}{4}$

$y=\dfrac{11}{4}$

Therefore, the directrix of the parabola is $y=\dfrac{11}{4}$ .

4 0

3 years ago