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sasho [114]
4 years ago
15

X^2-x+12 solve using the quadratic formula

Mathematics
1 answer:
devlian [24]4 years ago
4 0

The quadratic formula is x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}.

From the problem, a is 1, b is -1, and c is 12. Plugging in these values gives:

x=\frac{-(-1(-1)\pm\sqrt{(-1)^2-4(1)(12)} }{2(1)}

Because there is a square root of a negative number, there is no solution.

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What is the standard deviation of the data set given below?
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Answer:

The standard deviation of the set of values (2, 3, 6, 9, 10) is square root of 12.5 (\sqrt{12.5}) therefore OPTION C

7 0
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One vertex of a polygon is located at (3, –2). After a rotation, the vertex is located at (2, 3).
motikmotik

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What expression is equivalent to (x-3)^2
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3 years ago
7x + 2y = 7<br> -14x + 2y = -11<br> Solve by substitution
kvasek [131]

Answer:

x = 6/7, y = 1/2

Step-by-step explanation:

7x + 2y = 7

-14x + 2y = -11

1) 7x + 2y = 7

2y = 7 - 7x

2) -14x + 2y = -11

-14x + 7 - 7x = -11

- 21x = -11-7

- 21x = - 18

x = 18/21 = 6/7

3) 2y = 7 - 7x = 7 - 7*(6/7) = 7 - 6 = 1

2y = 1

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7 0
3 years ago
Special right triangles.<br> Find u.<br> Please help due in 30 min!
Svetlanka [38]

Answer:

2 km

Step-by-step explanation:

Reference angle = 45°

Opposite = u

Hypotenuse = 2√2 km

To find u, apply SOH:

Sin 45° = Opp/Hyp

Sin 45° = u/2√2

√2/2 = u/2√2 (sin 45 = √2/2)

Cross multiply

2*u = √2*2√2

2u = 4

Divide both sides by 2

u = 4/2

u = 2 km

7 0
3 years ago
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