Answer:
Explanation:
Density is m/V. Also, 1 liter = 1000 
. So, we get 0.890/(5*1000) = 
g/cm^3. You can convert this to kg/m^3 as well by multiplying it by 10. Depends which one you want.
Answer:
The particle theory of light was given by Isaac Netwon state that light was made of particles that allow light to undergo reflection and refraction.
The wave theory of light was contemporary of the particle theory of light given by Christiaan Huygens. It states that light was a wave that allows light to undergo reflection and refraction when passes through different mediums.
Answer:
13 nuclei
Explanation:
From the question, the fission of one nucleus produces three neutrons which causes more nuclei to undergo fission.
This implies that, after the first fission, three neutrons cause three nuclei to undergo fission. The three nuclei that underwent fission produces nine neutrons which causes the fission of nine nuclei.
All together we the number of nuclei that underwent fission as;
1 + 3 + 9 = 13 nuclei.
Explanation:
It's 112-100÷100*100= so 112-100 it's 12÷100 its 0.12 and *100 it's 12%
We have 6 moles of C (2*3=6), 14 moles of H (2*7=14) and 1 mol of O in 1 mol of <span>(C₃H₇)₂O:
Therefore:
1 mol of </span><span>(C₃H₇)₂O-------------6 moles of C
0.185 moles of </span><span>(C₃H₇)₂O------ x
x=(0.185 moles * 6 moles)/1 mole=1.11 moles
Answer: there are 1.11 moles of C in 0.185 moles of dipropyl ether
1 mol of C-----------------6.022*10²³ atoms
1.11 moles of C------------ x
x=(1.11 moles of C *6.022*10²³ atoms)/1 mole of C=6.68 *10²³ atoms
Answer: there are 6.68*10²³ atoms of C in 0.185 moles of dipropyl ether.
</span>
1 mole of <span>(C₃H₇)₂O-------------14 moles of H
0.185 moles of </span><span>(C₃H₇)₂O------ x
</span>
<span>x=(0.185 moles * 14 moles)/1 mole=2.59 moles
</span>
<span> there are 2.59 moles of H in 0.185 moles of dipropyl ether
1 mol -----------------------6.022*10²³ atoms
2.59 moles----------------- x
x=(2.59 moles * 6.022*10²³ atoms)/1 mol=1.56*10²⁴ atoms
Answer: there are </span><span>1.56*10²⁴ atoms in 0.185 moles of dipropyl ether.
</span>
<span>1 mol of <span>(C₃H₇)₂O-------------1 moles of C
0.185 moles of </span><span>(C₃H₇)--------- x</span>
x=(0.185 moles *1mol)/1 mol=0.185 moles
Answer: there are 0.185 moles of O in 0.185 moles of dipropyl ether.
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