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Readme [11.4K]
3 years ago
7

The name carbohydrate comes from the fact that many simple sugars have chemical formulae that look like water has simply been ad

ded to carbon. (The suffix hydrate from the Greek word hydor ("water") means "compound formed by the addition of water") The actual chemical structure of carbohydrates doesn't look anything like water molecules bonded to carbon atoms. But it is nevertheless possible to chemically extract all the hydrogen and oxygen from many simple carbohydrates as water, leaving only carbon behind. If you search the Internet for "reaction of sulfuric acid and sugar" you will find some impressive videos of this. Suppose you had (200. g) of ordinary table sugar, which chemists call sucrose, and which has the chemical formula C1,H2,0. Calculate the maximum mass of water you could theoretically extract. Be sure your answer has a unit symbol, and round it to the correct number of significant digits?
Chemistry
1 answer:
GREYUIT [131]3 years ago
7 0

Answer:

The maximum mass of water produced is  m__{H_2O}} =116 \ g

Explanation:

From the question we are told that

    The mass of  sucrose is m_s  = 200 \ g

    The chemical formula for  sucrose is  C_{12} H_{22} O_{11}

The chemical equation for the dissociation of sucrose  is

          C_{12} H_{22}O_{4} \to 12C + 11H_2O

The number of moles of  sucrose can be evaluated as

        n =  \frac{m}{Z}

Where Z is the molar mass of sucrose which has a constant value of

      Z  = 342 \ g/mol

So  

    n = \frac{200}{342}

   n =0.585

From the chemical equation one mole of sucrose produces 11 moles of water so  0.585 moles of sucrose will produce x moles of  water

Therefore

          x =  \frac{0.585 * 11}{1}

         x = 6.433 \ moles

Now the mass of water produced is mathematically represented as

         m__{H_2O}} =  x * Z__{H_2O}

 Where  Z__{H_2O} is the molar mass of water with a constant values of  Z__{H_2O}} = 18 \ g/mol

  So  

        m__{H_2O}} =  6.43* 18

       m__{H_2O}} =116 \ g

 

     

     

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The balanced equation for the neutralization of KOH is the following:

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To calculate the volume of HCl required, we can apply the following equation:

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So, the required volume of HCl is 541,54 mL

Have a nice day!
8 0
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