(i) We start by calculating the mass of sugar in the solution:
mass of sugar = concentration × solution mass
mass of sugar = 2.5/100 × 500 = 12.5 g
Then now we can calculate the amount of water:
solution mass = mass of sugar + mass of water
mass of water = solution mass - mass of sugar
mass of water = 500 - 12.5 = 487.5 g
(ii) We use the following reasoning:
If 500 g solution contains 12.5 g sugar
Then X g solution contains 75 g sugar
X=(500×75)/12.5 = 3000 g solution
Now to get the amount of solution in liters we use density (we assume that is equal to 1):
Density = mass / volume
Volume = mass / density
Volume = 3000 / 1 = 3000 liters of sugar solution
1,3,2
The coefficient multiplied by the subscript will give you how many atoms of the element there are.
So, if we plug in 1,3,2
There will be 2 Nitrogen and 6 Hydrogen in the reactants side of the equation. To balance this on the other side, we must put a 2 in order to get 2 Nitrogen and 6 Hydrogen again.
<span>2 phosphorus and 5 oxygen</span>
