Answer:
c
Explanation:
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Answer:
The answer to your question is U-234
Explanation:
Data
Thorium-234
beta emission twice
Definition
Beta emission is when a beta particle (electron) is emitted from an atomic nucleus.
First beta emission
²³⁴₉₀Th ⇒ ²³⁴₉₁Pa + e⁻
Second beta emission
²³⁴₉₁ Pa ⇒ ²³⁴₉₂U + e⁻
The atom will be Uranium-324
Answer:
the molecular formula of the compound is N2O4
Explanation:
- Find the empirical formula
mole of N present = mass of N divided by molar mass of N = 0.140/14 = 0.01 mole
mole of O present = mass of O divided by molar mass of O = 0.320/16 = 0.02 mole
Divide both by the smallest number of mole to determine the coefficient of each, the smallest number of mole is 0.01 thus:
quantity of N = 0.01/0.01 = 1
quantity of O = 0.02/0.01= 2
thus the empirical formula = NO2
- Now determine the molecular formula by finding the ratio of molecular formula and empirical formula
Molar mass of molecular formula = 92.02 amu = 92.02 g/mole
Molar mass of empirical formula NO2 = (14 + (16 x 2)) = 46 g/mole
the x factor = 92.02/46 = 2
Molecular formula = 2 x NO2 = N2O4
Answer:
1 mole of Al³+
Explanation:
Balanced chemical equation;
Al³⁺ + Na₃PO₄ → 3Na⁺ + AlPO₄
From the above chemical equation, it is evident that this is displacement reaction which is a reaction involving one atom or charge displacing another one in the chemical reaction.
In this reaction, Al³⁺ has a charge of +3 while Na⁺ has a charge of +1. When Al³⁺ displaces Na⁺, it meets an anion of PO₄³⁻ and since both charges are equal, i.e +3 and -3, there's is a mutual exchange of electrons and bond formation occurs.
The ratio of AlPO₄ to Al³⁺ is 1 : 1
I.e 1 mole of Al³⁺ produce 1 mole of AlPO₄
