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sashaice [31]
4 years ago
13

1.1x+9.9 factor out coefficient of the variable

Mathematics
1 answer:
zalisa [80]4 years ago
7 0
Ok....so look at the attached picture

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The formula for a buffer solution contains 1.24% w/v of boric acid. How many milli-liters of a 5% w/v boric acid solution should
Oksanka [162]

Answer: 248mL

Step-by-step explanation:

Given:

Concentration of buffer solution Cs = 1.24%w/v of boric acid

Concentration of boric acid solution Cb = 5 % w/v boric acid

For 1 liter of buffer solution, the weight of boric acid needed is:

mb = 1 × 1.24 = 1.24 unit weight

mb = Cb × Vb .....1

Cb = concentration of boric acid solution.

Vb = volume of boric acid solution needed.

mb = weight of boric acid needed.

From equation 1.

Vb = mb/Cb

Vb = 1.24/5

Vb = 0.248L

Vb = 248mL

4 0
3 years ago
Select all the correct answers.
evablogger [386]
Answer:
The 3rd and 4th option

Explanation:
A function only works when the input (x) only has one output (y).
The first, second, and the last option has the input has two or more outputs.

Fun Fact:
It is okay for the outputs to have more then in input, but not okay for the input to have more then one output.

I hope this help and have a nice day :)
6 0
3 years ago
What is the solution to the inequality below?​
FinnZ [79.3K]

Answer:A

Step-by-step explanation:

I used photomath lol

8 0
3 years ago
Read 2 more answers
Jarrett's puppy weighed 3 3/4 ounces at Birth. At 1 week old, the puppy weighed 5 1/8 ounces. At 2 weeks old, the puppy weighed
Ad libitum [116K]

Answer:  The answer is 7\dfrac{7}{8} ounces.

Step-by-step explanation: Given in the question the weight of Jarrett's puppy at birth, one week old and 2 weeks old are as follows:

b_0=3\dfrac{3}{4}=\dfrac{15}{4}~\textup{ounces},\\\\\\b_1=5\dfrac{1}{8}=\dfrac{41}{8}~\textup{ounces},\\\\\\b_3=6\dfrac{1}{2}=\dfrac{13}{2}~\textup{ounces}.

We can see that

b_1-b_0=b_2-b_1=\dfrac{11}{8}.

So, the weight of the baby will make an arithmetic progression with first term 'a' and common difference 'd' as follows:

b_0=\dfrac{15}{4},~~d=\dfrac{11}{8}.

Thus, the weight of the puupy after 3 weeks will be

b_3=b_0+3\times d=\dfrac{15}{4}+3\times\dfrac{11}{8}=\dfrac{30+33}{8}=\dfrac{63}{8}=7\dfrac{7}{8}~\textup{ounces}.

5 0
4 years ago
Read 2 more answers
The three cards below form a number pattern. The first two cards have been turned over to show their numbers
Korvikt [17]

Answer:

Most likely answers are either 6 or 8.

Step-by-step explanation:

The sequence could be of all even numbers, so 2, 4, 6, 8, etc.

Or of all powers of 2, starting at 2, so 2, 4, 8, 16, etc.

Since there are an infinite number of sequences that fit the pattern, you just have to choose the most likely.

7 0
3 years ago
Read 2 more answers
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