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Nostrana [21]
3 years ago
10

Due Today :( Please Help! show Work! Is the relation below a function? (1, 3), (-4, 0), (3, 1), (0, 4), (2, 3) Why or Why not? N

ame the domain and range

Mathematics
1 answer:
Sliva [168]3 years ago
4 0
<span>Since each x value maps to one and ONLY ONE y value, this means that this given relation is indeed a function. 
The domain is defined as, "</span> The domain<span> is the set of all possible x-values which will make the function "work", and will output real y-values." so I'm guessing the domain would be 1, 3, and 2 since they are independent integers that are positive. The range would be y<4, since the range is the spread of the possible y values. I hope this helps you out. </span>

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which of the three sets could not be the lengths of the sides of a triangle {6,10,12} {5,7,10} {4,4,9} {2,3,3}
Phoenix [80]

So for this, we will be applying the Triangle Inequality Theorem, which states that the sum of 2 sides must be greater than the third side for it to be a triangle. If any inequality turns out to be false, then the set cannot be a triangle.

A+B>C\\A+C>B\\B+C>A

<h2>First Option: {6, 10, 12}</h2>

Let A = 6, B = 10, and C = 12:

6+10>12\\16>12\ \textsf{true}\\\\6+12>10\\18>10\ \textsf{true}\\\\12+10>6\\22>6\ \textsf{true}

<h2>Second Option: {5, 7, 10}</h2>

Let A = 5, B = 7, and C = 10

5+7>10\\12>10\ \textsf{true}\\\\5+10>7\\15>7\ \textsf{true}\\\\10+7>5\\17>5\ \textsf{true}

<h2>Third Option: {4, 4, 9}</h2>

Let A = 4, B = 4, and C = 9

4+4>9\\8>9\ \textsf{false}\\\\4+9>4\\13>4\ \textsf{true}\\\\4+9>4\\13>4\ \textsf{true}

<h2>Fourth Option: {2, 3, 3}</h2>

Let A = 2, B = 3, and C = 3

2+3>3\\5>3\ \textsf{true}\\\\2+3>3\\5>3\ \textsf{true}\\\\3+3>2\\6>2\ \textsf{true}

<h2>Conclusion:</h2>

Since the third option had an inequality that was false, <u>the third option cannot be a triangle.</u>

5 0
3 years ago
Read 2 more answers
65) Driving time: A family is planning to drive 549 miles from their home in Lincoln, Nebraska, to Mount
musickatia [10]

549 Divided By 61 Is The Number Of Hours

5 0
3 years ago
How do i figure out the degrees?
liraira [26]

Answer:

  41°

Step-by-step explanation:

This problem involving the Law of Cosines has been mostly worked for you. The value of the cosine is the solution to the remaining one-step linear equation. The inverse cosine function (cos⁻¹ or arccos) is used to find the angle from the value of the cosine.

  -1125 = -1500·cos(A)

  cos(A) = -1125/-1500 = 3/4 . . . . . divide by -1500 (this is the one step)

  A = arccos(3/4) ≈ 41.4096°

The angle formed by the lines to the lampposts is about 41°.

__

<em>Additional comment</em>

If you find the angle using the ACOS( ) function of a spreadsheet, you will always get the result in radians. Most calculators offer the choice of units for angles, so be sure you set the mode appropriately.

In the calculator screenshot, there is a decimal point in the fraction to force the angle result to be displayed as a numerical value. Otherwise, this calculator shows cos⁻¹(3/4), which isn't terribly helpful.

3 0
2 years ago
Six more than nine times a number is 456 translate to an equation then solve
Sliva [168]

6+9x=456

Subtract 6 from both sides

6-6+9x = 456-6

9x = 450

Divide each side by 9

X = 50

Plug it in 6+9(50) = 456

6+450 = 456

8 0
3 years ago
Read 2 more answers
In the digram GH bisects FGI what is the answer for C.
zhannawk [14.2K]

The line GH bisects The triangle FGI meaning it divides it into two equal parts <em>(that is the definition if bisection); </em>therefore, the angles FGH and HGI are equal:

3x-2=4x-13

Now let us add 2 to both sides gives

3x=4x-11

subtracting 4x from both sides gives

-x=-11x=11.

Hence, x = 11.

The measure of FGH is

3x-2=3(11)-2=31

(B)

The measure of HGI is

4x-13=4(11)-13=31

(C)

The measure of FGI is the sum of HGI and FGH:

\begin{gathered} \text{FGI}=\text{HGI}+\text{FGH}=31+31 \\ FGI=62^o \end{gathered}

<em />

7 0
1 year ago
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