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DerKrebs [107]
3 years ago
15

Given vectors a=(4,1) and b=(-5,2) find -3a+4b

Mathematics
1 answer:
sertanlavr [38]3 years ago
3 0
  a=(4,1) and b=(-5,2)

-3a+4b=-3(4,1) + 4(-5,2)=(-12,-3) + (-20,8) = (-32,5)



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8 0
4 years ago
Divide these polynomials. (8x³ + 2x² - 7x + 2) ÷ (2x - 1)
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6 0
3 years ago
WILL GIVE BRAINLIEST
Papessa [141]
<span>the particle's initial position is at t=0, x = 0 - 0 + 4 = 4m

velocity is rate of change of displacement = dx/dt = d(t^3 - 9t^2 +4)/dt
= 3t^2 - 18t

acceleration is rate of change of velocity = d(3t^2 -18t)/dt
= 6t - 18

</span><span>the particle is stationary when velocity = 0, so 3t^2 - 18t =0
</span>3t*(t - 6) = 0
t = 0 or t = 6s

acceleration = 6t - 18 = 0
t = 3s
at t = 3s, velocity = 3(3^2) -18*3 = -27m/s
displacement = 3^3 - 9*3^2 +4 = -50m


6 0
4 years ago
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