We have that
y=x²----> equation 1<span>
y=x+2-----> equation 2
multiply equation 1 by -1
-y=-x</span>²
add equation 1 and equation 2
-y=-x²
y=x+2
------------
0=-x²+x+2-------------> -x²+x+2=0-----> x²-x-2=0
Group terms that contain the same variable, and move the
constant to the opposite side of the equation
(x²-x)=2
<span>Complete
the square. Remember to balance the equation by adding the same constants
to each side
</span>(x²-x+0.5²)=2+0.5²
Rewrite as perfect squares
(x-0.5)²=2+0.5²
(x-0.5)²=2.25-----> (x-0.5)=(+/-)√2.25-----> (x-0.5)=(+/-)1.5
x1=1.5+0.5-----> x1=2
x2=-1.5+0.5---- > x2=-1
for x=2
y=x²----> y=2²----> y=4
the point is (2,4)
for x=-1
y=x²----> y=(-1)²---> y=1
the point is (-1,1)
the answer isthe solution of the system are the points(2,4) and (-1,1)
1 is wrong because the measurements do not work for the pythagorean theorem.
3 is wrong because using the pythagorean theorem with those measurements would not work.
4 is wrong because the only way that 4 would work is if the hypotenuse was 3√2 not 3√3
The correct answer is 2 because that is the only one that actually works with the pythagoran theorem.
√41^2 = 41
5^2 + 4^2 = 25 + 16 = 41
41 = 41
Answer:
Dimensions of the poster
Width 29.10 cm
Height 38.80 cm
A(min) = 1129.08 cm²
Step-by-step explanation:
Printed area = 390 cm² = Ap
Lets call x and y dimensions of printed area
x width
y height
Then Ap = x*y and
y = Ap/x ⇒ y = 390/x
Then total area of the poster is:
A(t) = ( x + 12 ) * ( y + 16 ) and y = 390/x
A as a function of x
A(x) = ( x + 12 ) * ( 390/x + 16 ) ⇒ A(x) = 390 + 16x + 4680/x + 192
A(x) = 582 + 16x + 4680/x (1)
Taking derivatives
A´(x) = 16 - (4680/x²) ⇒ A´(x) = 0
[ 16x² -4680] /x² = 0 16x²- 4680 = 0 ⇒ x² = 4680/16
x = 17.10 cm and y = 390/x y = 390/17.10 y = 22.80 cm
A(t) = ( 17.10 + 12 ) * ( 22.80 + 16 )
A(t) = 29.10 * 38.80
A(t) = 1129.08 cm²
If we substitute in equation (1) the value of x ( 17.10) we see A(x) > 0
Then there is a minimun at the point x = 17.10
The answer for your question is 13.
The measure of angle PNL = 43
