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3 years ago

This test is used to determine the end behavior of a polynomial function.

Mathematics

1 answer:

Schach [20]3 years ago

6 0

Leading Coefficient Test is the correct answer.

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HELP I WILL GIVE BRAINLIEST

Maksim231197 [3]

Answer: D

Step-by-step explanation:

-4 < -w

w > -4

Since it doesn't have an equal sign, its an open circle. Since its greater than -4, it is going to the right, so shade right.

Answer is D

3 0

2 years ago

Activity 1<br>Calculate the following:<br>1. 68% of 418,

il63 [147K]

Answer:

284.24

Step-by-step explanation:

by multiplying 0.68 to 418 we get 68% of 418

7 0

2 years ago

Read 2 more answers

From a height of 50 meters above sea level on a cliff, two ships are sighted due west. The angles of depression are 61° and 28°.

Olenka [21]

Answer:

The ships are 66 meters apart.

Step-by-step explanation:

For the sake of convenience, let us label ships A and B

As shown in the figure, the distances to the ships from right triangles.

The distance to the ship A is $d_1$ and it is given by

$tan (61^o)= \dfrac{50}{d_1}$

$d_1=\dfrac{50}{tan (61^o)}$

$\boxed{d_1= 27.71m}$

And the distance to the ship B is $d_2$ and is given by

$tan (28^o)= \dfrac{50}{d_2}$

$d_2=\dfrac{50}{tan (28^o)}$

$\boxed{ d_2=94.04m}$

Therefore, the distance $d$ between the ships A and B is

$d= d_2-d_1=94.04-27.7\\\\\boxed{d=66m}$

In other words, the ships are 66 meters apart.

8 0

3 years ago

Read 2 more answers

Solve 5w^2+25=115, Where w is a real number.

MArishka [77]

Answer:

w=+/-4.24 or whatever could be either since its squared

Step-by-step explanation:

subtract 25 so 5x^2=90. divide by 5 so w^2=18 then square root to get rid of the ^2 so w=+/-4.24

4 0

2 years ago

Find the exact value of cos(sin^-1(-5/13))

son4ous [18]

bearing in mind that the hypotenuse is never negative, since it's just a distance unit, so if an angle has a sine ratio of -(5/13) the negative must be the numerator, namely -5/13.

$\bf cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right] \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{then we can say that}~\hfill }{sin^{-1}\left( -\cfrac{5}{13} \right)\implies \theta }\qquad \qquad \stackrel{\textit{therefore then}~\hfill }{sin(\theta )=\cfrac{\stackrel{opposite}{-5}}{\stackrel{hypotenuse}{13}}}\impliedby \textit{let's find the \underline{adjacent}}$

$\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{13^2-(-5)^2}=a\implies \pm\sqrt{144}=a\implies \pm 12=a \\\\[-0.35em] ~\dotfill\\\\ cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right]\implies cos(\theta )=\cfrac{\stackrel{adjacent}{\pm 12}}{13}$

le's bear in mind that the sine is negative on both the III and IV Quadrants, so both angles are feasible for this sine and therefore, for the III Quadrant we'd have a negative cosine, and for the IV Quadrant we'd have a positive cosine.

8 0

2 years ago