Answer:
0.3446
Step-by-step explanation:
P(X≥2) = 1 − P(X<2)
P(X≥2) = 1 − P(X=0) − P(X=1)
P(X≥2) = 1 − ₆C₀ (0.2)⁰ (0.8)⁶ − ₆C₁ (0.2)¹ (0.8)⁵
P(X≥2) = 1 − 0.2621 − 0.3932
P(X≥2) = 0.3446
Answer:
Fertilizer B produced a 15% greater yield
Step-by-step explanation:
Mean yield fertilizer A = 20.2
Mean yield fertilizer B = 23.2
Thus, 23.2 − 20.2
20.2
= 0.1485 ≈ 0.15 or 15%
Answer:
option (b) 700 mg to 740 mg
Step-by-step explanation:
Data provided;
The weight of candies is approximately normally distributed with mean 720 milligrams (mg)
this means that the most of the candies weight lies around the 720 milligrams
i.e
the most of the weight will be distributed as:
Mean ± standard deviation
here, the mean is 720 milligrams
thus,
the weights will lie within the range of some standard deviation above and below the mean and this is justified by the option (b) 700 mg to 740 mg
Hence,
the correct answer is option (b) 700 mg to 740 mg
Answer:
The scale of the copy of the ticket is
Step-by-step explanation:
we know that
To find the scale divide the long of the copy of a ticket by the long of the original of a ticket
so