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vovangra [49]
3 years ago
7

Two suppliers manufacture a plastic gear used in a laser printer. The impact strength of these gears measured in foot-pounds is

an important characteristic. A random sample of 10 gears from supplier 1 results in $$\overline{\mbox{x}}_1=290$$ and $$s_1 = 12$$, and another random sample of 16 gears from the second supplier results in $$\overline{\mbox{x}}_2=321$$ and $$s_2 = 22$$.
a. Is there evidence to support the claim that supplier 2 provides gears with higher mean impact strength? Use α = 0.05, and assume that both populations are normally distributed but the variances are not equal.
What is the P-value for this test?
b. Do the data support the claim that the mean impact strength of gears from supplier 2 is at least 25 foot-pounds higher than that of supplier 1? Make the same assumptions as in part (a).
c. Construct a confidence interval estimate for the difference in mean impact strength, and explain how this interval could be used to answer the question posed regarding supplier-to-supplier differences.

Mathematics
1 answer:
solong [7]3 years ago
6 0

Step-by-step explanation:

The explanation and the graphical representation is attached

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Common difference: 6

First term: 7

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Third term: 19

Fourth term: 25

Fifth term: 31

I hope this is correct and helps!

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Consider the function represented by 9x+3y= 12 with x as the independent variable. How can this function be written using
Ivenika [448]

Answer:

f(x)=-3x+4

(can't see some of your choices)

Step-by-step explanation:

We want x to be independent means we want to write it so when we plug in numbers we can just choose what we want to plug in for x but y's value will depend on our choosing of x.

So we need to solve for y.

9x+3y=12

Subtract 9x on both sides

     3y=-9x+12

Divide both sides by 3:

     y=-3x+4

Replace y with f(x).

    f(x)=-3x+4

6 0
3 years ago
The sales of a grocery store had an average of $8,000 per day. The store introduced several advertising campaigns in order to in
oksano4ka [1.4K]

Answer:

Null hypothesis:\mu \leq 8000  

Alternative hypothesis:\mu > 8000  

z=\frac{8300-8000}{\frac{1200}{\sqrt{64}}}=2  

p_v =P(Z>2)=0.0228  

Step-by-step explanation:

1) Data given and notation  

\bar X=8300 represent the sample mean  

\sigma=1200 represent the population standard deviation  

n=64 sample size  

\mu_o =800 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

2) State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 8000, the system of hypothesis are :  

Null hypothesis:\mu \leq 8000  

Alternative hypothesis:\mu > 8000  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

3) Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{8300-8000}{\frac{1200}{\sqrt{64}}}=2  

4) P-value  

Since is a one-side upper test the p value would given by:  

p_v =P(Z>2)=0.0228  

5) Conclusion  

If we compare the p value and the significance level assumed, for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is significantly higher than $8000.  

4 0
3 years ago
Please help me It’ll help a lot
Digiron [165]

Answer:

heyy

the answers "20"

Step-by-step explanation:

Okay using the x that we have we find 40 and plug that into the graph and we have 20 :p

7 0
2 years ago
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