Suppose that 7 cards are drawn from a? well-shuffled deck of 52 cards. What is the probability that all 7 are heartshearts?
1 answer:
There are 13 hearts in the deck of 52.
If we want to simply choose 7 of them, we use combinatorics, and not permutations.
Thus, the total number of ways to choose 7 of the 13 hearts, is: ¹³C₇ or 1716 ways.
The total in our sample space is simply choosing 7 of the 52 cards, which is: ⁵²C₇ or 133 784 560.
Thus, the probability becomes:
If we want to simply choose 7 of them, we use combinatorics, and not permutations.
Thus, the total number of ways to choose 7 of the 13 hearts, is: ¹³C₇ or 1716 ways.
The total in our sample space is simply choosing 7 of the 52 cards, which is: ⁵²C₇ or 133 784 560.
Thus, the probability becomes:
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Answer:
23rd term of the arithmetic sequence is 118.
Step-by-step explanation:
In this question we have been given first term a1 = 8 and 9th term a9 = 48
we have to find the 23rd term of this arithmetic sequence.
Since in an arithmetic sequence
here a = first term
n = number of term
d = common difference
since 9th term a9 = 48
48 = 8 + (9-1)d
8d = 48 - 8 = 40
d = 40/8 = 5
Now
= 8 + (23 -1)5 = 8 + 22×5 = 8 + 110 = 118
Therefore 23rd term of the sequence is 118.