Suppose that 7 cards are drawn from a? well-shuffled deck of 52 cards. What is the probability that all 7 are heartshearts?
1 answer:
There are 13 hearts in the deck of 52.
If we want to simply choose 7 of them, we use combinatorics, and not permutations.
Thus, the total number of ways to choose 7 of the 13 hearts, is: ¹³C₇ or 1716 ways.
The total in our sample space is simply choosing 7 of the 52 cards, which is: ⁵²C₇ or 133 784 560.
Thus, the probability becomes:
If we want to simply choose 7 of them, we use combinatorics, and not permutations.
Thus, the total number of ways to choose 7 of the 13 hearts, is: ¹³C₇ or 1716 ways.
The total in our sample space is simply choosing 7 of the 52 cards, which is: ⁵²C₇ or 133 784 560.
Thus, the probability becomes:
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It has been given that y varies inversely with x, therefore the equation for this relationship is as follows;
y =
\
when y = -18 and x = 6
-18 = k/ 6 ---1)
We need to find x when y = 5
5 = k/x
when we divide 1)/2), k gets cancelled
x = -18*6/5
x = -21.6
when y = 5, then x = -21.6
y =
when y = -18 and x = 6
-18 = k/ 6 ---1)
We need to find x when y = 5
5 = k/x
when we divide 1)/2), k gets cancelled
x = -18*6/5
x = -21.6
when y = 5, then x = -21.6