NEED ANSWER ASAP!!!

Convert the following radian angle into degrees.

NeTakaya

The degree of the radian angle 0.11 is $6.3^{\circ}$

Explanation:

It is given that the radian angle is 0.11

We need to determine the degrees of the radian angle.

To convert the radian into degrees, let us multiply the radian with $\left(\frac{180}{\pi}\right)$

Thus, we have,

$0.11\times\left(\frac{180}{\pi}\right)=\frac{19.8}{\pi}$

It is given that $\pi=3.14$

Substituting $\pi=3.14$ in the above expression, we have,

$\frac{19.8}{3.14} =6.303...$

Rounding off to the nearest tenth, we have,

$6.3^{\circ}$

Thus, the degree of the radian angle 0.11 is $6.3^{\circ}$

4 0

2 years ago

I need someone to explain on how to do this problem.

weqwewe [10]

Answer:

I think it's x=-12 for the buttom one

Step-by-step explanation:

I think when you get open equations like these you would asume 1 is there so rewrite it as 2x + 25 = 1

so take the 25 away from 1. to do that we need to do the opisite of +

2x + 25 = 1

1 - 25 = -24

rewrite

2x = -24

take the 2 away. oppisite of mulitplication is division. so divide 2 by -24

-24 divided by 2 = -12

Hope this helps! Please mark as brainliest! Thanks! If you need me to solve the top one too, I'll do it! Just comment bellow. :D

5 0

3 years ago

Read 2 more answers

The product of 5 and a number y

zysi [14]

Answer: 5y

Step-by-step explanation:

Product means the multiplication of, so taking the product of 5 and y we simply have;

5*y=5y

8 0

2 years ago

Read 2 more answers

Find the roots of the equation<br> x ^ 2 + 3x-8 ^ -14 = 0 with three precision digits

scoray [572]

Answer:

Step-by-step explanation:

Given quadratic equation:

$x^{2} + 3x - 8^{- 14} = 0$

The solution of the given quadratic eqn is given by using Sri Dharacharya formula:

$x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}$

The above solution is for the quadratic equation of the form:

$ax^{2} + bx + c = 0$

$x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}$

From the given eqn

a = 1

b = 3

c = $- 8^{- 14}$

Now, using the above values in the formula mentioned above:

$x_{1, 1'} = \frac{- 3 \pm \sqrt{3^{2} - 4(1)(- 8^{- 14})}}{2(1)}$

$x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})})$

$x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})} - 3)$

Now, Rationalizing the above eqn:

$x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(- 8^{- 14})} - 3)\times (\frac{\sqrt{9 - 4(- 8^{- 14})} + 3}{\sqrt{9 - 4(- 8^{- 14})} + 3}$

$x_{1, 1'} = \frac{1}{2}.\frac{(\pm {9 - 4(- 8^{- 14})^{2}} - 3^{2})}{\sqrt{9 - 4(- 8^{- 14})} + 3}$

Solving the above eqn:

$x_{1, 1'} = \frac{2\times 8^{- 14}}{\sqrt{9 + 4\times 8^{-14}} + 3}$

Solving with the help of caculator:

$x_{1, 1'} = \frac{2\times 2.27\times 10^{- 14}}{\sqrt{9 + 42.27\times 10^{- 14}} + 3}$

The precise value upto three decimal places comes out to be:

$x_{1, 1'} = 0.758\times 10^{- 14}$

5 0

3 years ago

Tom Henderson takes out a $120,000 mortgage. He paid 1.6% of the loan amount in closing costs and $8,962.49 in total interest th

Eva8 [605]

119998.40 120000-1.60=119998.4 Hope I helped out some!!

5 0

3 years ago