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Svet_ta [14]
3 years ago
5

estructura lewis del Sulfuro de potasio (K2S) y la del óxido de boro (B2O3). Ayuda es urgente porfaaaaaaaaa!!!

Chemistry
1 answer:
N76 [4]3 years ago
4 0

Answer:

ok

Explanation:

you want me to figure this out in that language into english ok

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½O2(g) + H2(g) ⇌ H2O(g)
ira [324]

Answer:

-241.826 kJ·mol⁻¹;  -146.9 J·K⁻¹mol⁻¹; 664.6 J·K⁻¹mol⁻¹; spontaneous

Explanation:

                        ½O₂(g)   +  H₂(g) ⟶ H₂O(g)

ΔHf°/kJ·mol⁻¹:      0                0        -241.826

S°/J·K⁻¹mol⁻¹:   205.0         130.6       188.7

1. ΔᵣH

ΔᵣH = products -reactants = -241.826 -(0 + 0) = -241.826 kJ·mol⁻¹

2. ΔᵣS

ΔᵣS = products - reactants = 188.7 - (205.0 + 130.6) = 188.7 - 335.6 = -146.9 J·K⁻¹mol⁻¹

3. ΔS(univ)

\begin{array}{rcl}\Delta S_{\text{univ}} &=& \Delta S_{\text{sys}}  +\Delta S_{\text{surr}}\\\\ &=& \Delta S_{\text{sys}}  -\dfrac{\Delta H_{\text{sys}}}{T}\\\\& = & -146.9 - \dfrac{-241826}{298}\\\\& = & -146.9 + 811.5\\& = & \mathbf{664.6 \,\, J\cdot K^{-1}mol^{-1}}\\\end{array}

4. Spontaneity

\begin{array}{rcl}\Delta G &=& \Delta H - T\Delta S\\& = & -241.826 - 298 \times (-0.1469)\\& = & -241.826 + 43.776\\& = &  \textbf{-198.050 kJ}\cdot\textbf{mol}^{\mathbf{-1}}\\\end{array}

ΔG is negative, so the reaction is spontaneous.

4 0
3 years ago
How does litmus indicator work​
makkiz [27]
Answer:

The substance which responds to the change in the concentration of the hydronium ions in solution by changing its color is known as an indicator.
6 0
3 years ago
Name physical properties
Paraphin [41]

Answer:

<u>Some examples of physical properties are: </u>

color (intensive)

density (intensive)

volume (extensive)

mass (extensive)

boiling point (intensive): the temperature at which a substance boils.

melting point (intensive): the temperature at which a substance melts.

Explanation:

Hope this helped! <3

8 0
3 years ago
Which of the following is an oxidation reaction? A. AuCl4- → AuCl 2- B. Mn7+ → Mn2+ C. Co3+ → Co2+ D. Cl2 → ClO3-
OLga [1]
D. There must be oxygen added. 2 of them don't even have oxygen anywhere in the formula, and the 3rd loses oxygen, which is reduction.
6 0
3 years ago
Read 2 more answers
Write the mechanism of the reaction of methyl benzoate to form methyl 2-nitrobenzoate.
Igoryamba
The question is incorrect, nitration of methylbenzoate occurs at 3 position to get, methyl 3-nitrobenzoate. 

This is because, in present reaction the reactant i.e. methylbenzoate, has low electron density at m-position.

Due to this, NO2+ prefentially attaches m-position to form  methyl 3-nitro benzoate as the product. 

A detailed reaction mechanism for formation of product is provided below.

3 0
4 years ago
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