Answer:
2 HI(aq) + Ba²⁺(aq) + 2 OH⁻(aq) → 2 H₂O(l) + Ba²⁺(aq) + 2I⁻(aq)
Explanation:
Let's consider the following balanced molecular equation.
2 HI(aq) + Ba(OH)₂(aq) → 2 H₂O(l) + BaI₂(aq)
In the complete ionic equation we include all the ions and the species that do not dissociate in water. HI is a weak electrolyte so it exists mostly in the molecular form. H₂O has a very low equilibrium constant (Kw = 10⁻¹⁴) si it exists mainly in the molecular form.
2 HI(aq) + Ba²⁺(aq) + 2 OH⁻(aq) → 2 H₂O(l) + Ba²⁺(aq) + 2I⁻(aq)
Answer:
soluble because all compounds containing K are soluble
Explanation:
Most metal hydroxides are insoluble. However, alkali metal hydroxides (such as KOH and NaOH) are very soluble.
In the case of KOH, the K cation is attracted to the electronegative oxygen on water. The OH anion is capable of hydrogen bonding to the water. (Notice how OH⁻ is simply the deprotonated form of water.)
I believe it the answer is 3412
