The answer to your question is 4.11 if I’m correct
Answer:
we have the equation y = (1/2)*x + 4.
now, any equation that passes through the point (4, 6) will intersect this line, so if we have an equation f(x), we must see if:
f(4) = 6.
if f(4) = 6, then f(x) intersects the equation y = (1/2)*x + 4 in the point (4, 6).
If we want to construct f(x), an easy example can be:
f(x) = y = k*x.
such that:
6 = k*4
k = 6/4 = 3/2.
then the function
f(x) = y= (3/2)*x intersects the equation y = (1/2)*x + 4 in the point (4, 6)
Answer:
y-intercept: (0, 5); slope: 1/4
Step-by-step explanation:
The slope (m) is found from ...
m = (y2 -y1)/(x2 -x1)
Using the first two points in the table, this is ...
m = (8 -6)/(12 -4) = 2/8 = 1/4 . . . . . eliminates choices A and C
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Then, the point-slope form of the equation of the line can be written as ...
y -y1 = m(x -x1)
y -6 = (1/4)(x -4) . . . fill in known values
y = 1/4x -1 +6 . . . . . add 6
y = 1/4x +5
Then the value of y when x=0 is ...
y = 0 +5 = 5
So, the y-intercept is (0, 5) and the slope is 1/4, matching the last choice.
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