The first thing to do is to work out the biggest number that goes into bother 24 and 3. As the only that goes into three- other than 1- is itself, one can assume this is the number we are looking for.
Next, divide bother numbers by 3.
24 / 3 = 8
3 / 3 = 1
You now take 3 out of the brackets, and leave 8 and 1. 24x / 3 = 8x.
3(8x + 1)
Hello! The answer should be B: 6i

. Since the square root is above a negative, an imaginary number would come out. Because of this, you can easily recognize that it would be B.
However, if you can't, you could use the calculator to check (ignoring the negatives), 6

is equal to

.
The final answer should be B.
Two or zero expresses the possible number of positive real solutions for the given polynomial equation.
Answer: Option D
<u>Step-by-step explanation:</u>
Given equation:

First, we put hit and trial method to find out the one solution. So, if we put x=4 then the above expression will become zero. We can also write the above expression as

We know the formula,
, make use of this, we get

So, 
Hence, from the above expression, we have three values of x as x= 4, 2.64 and -2.64
19,7,and 61 im not sure about the last one
I would say 465 since they go back and forth twice which is 155 x 3