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leva [86]
3 years ago
9

I NEED HELP!!!! WILL MARK BRAINLIEST!!!

Mathematics
1 answer:
SashulF [63]3 years ago
6 0

Answer: J

Step-by-step explanation:

x=8, so substitute and Length=12 Width=9

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JKLM is a rhombus. KM is 20 and JL is 48. Find the perimeter of the<br><br> rhombus.
anygoal [31]

Answer:

104 units

Step-by-step explanation:

Given

Shape: Rhombus

JL = 48

KM = 20

Required

Determine the perimeter

The given parameter are the diagonals of the rhombus.

The perimeter (from diagonals) is calculated as thus:

P = 2\sqrt{(JL)^2 + (KM)^2}

Substitute values for JL and KM

P = 2\sqrt{48^2 + 20^2}

P = 2\sqrt{2304 +400}

P = 2\sqrt{2704}

P = 2 * 52

P = 104

<em>Hence, the perimeter is 104 units</em>

5 0
2 years ago
PLZ HELP ME I DO NOT UNDERSTAND
tekilochka [14]

Answer:

b is the answer

Step-by-step explanation:

8 0
3 years ago
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What is the perimeter of a triangle with sides<br> 11 inches, 5 inches, and 12 inches in length?
natulia [17]

Answer: 28 in.

Step-by-step explanation:

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2 years ago
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Which of the following could be the graph of the line y = 3x - 2?
morpeh [17]

You didn't give a graph but I will visualize what it looks like for you.

The line is going through (0,-2) because that is the y-intercept.

The line has a slope of 3.

So, the line goes through:

(1,1)

(2,4)

(3,7)

(4,10)

(5,13)

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2 years ago
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What is the area of a sector with a central angle of 108 degrees and a diameter of 21.2 cm?
Rasek [7]

Answer:

105.84\ cm^2

Step-by-step explanation:

step 1

Find the area of the circle

The area of the circle is

A=\pi r^{2}

we have

r=21.2/2=10.6\ cm ----> the radius is half the diameter

substitute

A=\pi (10.6)^{2}

A=112.36\pi\ cm^2

step 2

Find the area of a sector

Remember that

The area of the circle subtends a central angle of 360 degrees

so

using proportion

Find out the area of a sector with a central angle of 108 degrees

\frac{112.36\pi}{360^o}=\frac{x}{108^o}\\\\x=112.36\pi(108)/360\\\\x=33.708\pi\ cm^2

assume

\pi=3.14

substitute

33.708(3.14)=105.84\ cm^2

7 0
3 years ago
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