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4 years ago

Please help meeeeeeeeeeeeeeee

Mathematics

1 answer:

erik [133]4 years ago

5 0

Answer:

1) B

2) D

3) A

4) B

Step-by-step explanation:

We use a closed/filled in dot in math to represent an inequality where we have ≤ or ≥ and an open dot when its < or >. This is to represent that from the inequality we are also including the = component of the inequality.

After you know this, its pretty simple to work out which way the numbers go on the number line when its greater or less than depending on the question

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How many combinations of four books can be made from eight different books? 24 70 1,680?

djverab [1.8K]

Answer:

Step-by-step explanation:

four books can be made from eight different books

4 books to be chosen from 8 books

The order does not matters so we use Combination.

four books can be made from eight different books, so we find 8C4

$nCr= \frac{n!}{r!(n-r)!}$

$8C4= \frac{8!}{4!(8-4)!}$

$8C4= \frac{8!}{4!(4)!}$

$8C4= \frac{8*7*6*5*4!}{4!(4)!}=70$

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4 years ago

1.The value of 8 dimes is

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3 years ago

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Which is greater 5/6 or 1/3

Yuki888 [10]

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3 years ago

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(X^2+y^2+x)dx+xydy=0 Solve for general solution

aksik [14]

Check if the equation is exact, which happens for ODEs of the form

$M(x,y)\,\mathrm dx+N(x,y)\,\mathrm dy=0$

if $\frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}$ .

We have

$M(x,y)=x^2+y^2+x\implies\dfrac{\partial M}{\partial y}=2y$

$N(x,y)=xy\implies\dfrac{\partial N}{\partial x}=y$

so the ODE is not quite exact, but we can find an integrating factor $\mu(x,y)$ so that

$\mu(x,y)M(x,y)\,\mathrm dx+\mu(x,y)N(x,y)\,\mathrm dy=0$

is exact, which would require

$\dfrac{\partial(\mu M)}{\partial y}=\dfrac{\partial(\mu N)}{\partial x}\implies \dfrac{\partial\mu}{\partial y}M+\mu\dfrac{\partial M}{\partial y}=\dfrac{\partial\mu}{\partial x}N+\mu\dfrac{\partial N}{\partial x}$

$\implies\mu\left(\dfrac{\partial N}{\partial x}-\dfrac{\partial M}{\partial y}\right)=M\dfrac{\partial\mu}{\partial y}-N\dfrac{\partial\mu}{\partial x}$

Notice that

$\dfrac{\partial N}{\partial x}-\dfrac{\partial M}{\partial y}=y-2y=-y$

is independent of x, and dividing this by $N(x,y)=xy$ gives an expression independent of y. If we assume $\mu=\mu(x)$ is a function of x alone, then $\frac{\partial\mu}{\partial y}=0$ , and the partial differential equation above gives