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Reika [66]
3 years ago
14

What is a outlier for mathematics

Mathematics
2 answers:
Nonamiya [84]3 years ago
8 0

Answer: An outlier stands out from all the other numbers.

Example: 1, 2, 3, 4, 6, 80. In this case, the outlier would be 80.

finlep [7]3 years ago
7 0

Answer:

A value that "lies outside" (is much smaller or larger than) most of the other values in a set of data. For example in the scores 25,29,3,32,85,33,27,28 both 3 and 85 are "outliers". Outliers.

Step-by-step explanation:

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Rewrite the expression by combining like terms. 3y + 5x2 + 10x + 2x2 + 15x – 3y​
EleoNora [17]

Answer:

7x²+ 25x

Step-by-step explanation:

7 0
3 years ago
Relationship between s and b helpppppp pleaseeee anyoneeeee
Harrizon [31]

Answer:

see the table below

Step-by-step explanation:

s b

1 18

3 23

5 27

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8 0
3 years ago
Here are two triangles.
devlian [24]

Answer: no its a reflection.

Step-by-step explanation:

you can see that no matter how you rotate triangle be it can not get all the angles to match but if you were to fold it in half they are a perfect fit. :)

4 0
3 years ago
An instructor gives her class the choice to do 7 questions out of the 10 on an exam.
Maksim231197 [3]

Answer:

(a) 120 choices

(b) 110 choices

Step-by-step explanation:

The number of ways in which we can select k element from a group n elements is given by:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways in which a student can select the 7 questions from the 10 questions is calculated as:

10C7=\frac{10!}{7!(10-7)!}=120

Then each student have 120 possible choices.

On the other hand, if a student must answer at least 3 of the first 5 questions, we have the following cases:

1. A student select 3 questions from the first 5 questions and 4 questions from the last 5 questions. It means that the number of choices is given by:

(5C3)(5C4)=\frac{5!}{3!(5-3)!}*\frac{5!}{4!(5-4)!}=50

2. A student select 4 questions from the first 5 questions and 3 questions from the last 5 questions. It means that the number of choices is given by:

(5C4)(5C3)=\frac{5!}{4!(5-4)!}*\frac{5!}{3!(5-3)!}=50

3. A student select 5 questions from the first 5 questions and 2 questions from the last 5 questions. It means that the number of choices is given by:

(5C5)(5C2)=\frac{5!}{5!(5-5)!}*\frac{5!}{2!(5-2)!}=10

So, if a student must answer at least 3 of the first 5 questions, he/she have 110 choices. It is calculated as:

50 + 50 + 10 = 110

6 0
3 years ago
Please help me with this ASAP
Digiron [165]

Answer:

270.00 divided by 32 = about $8.44

4 0
2 years ago
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