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Vesna [10]
3 years ago
11

Round 164.58 to the nearest whole number.​

Mathematics
1 answer:
AleksAgata [21]3 years ago
7 0
165

djshshsbehehwhwhwjwjwp
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Once again, I need help.
Fittoniya [83]

Answer:

128 sandwiches

Step-by-step explanation:

The pattern is x4. 32 * 4 = 128

6 0
4 years ago
Which phrase bost describes the translation from the graph y=(x+2)^2 to the graph of <br> y=x^2 + 3?
maksim [4K]

Answer:

C

Step-by-step explanation:

2 units right and 3 units up

7 0
3 years ago
A two digit number is such that the sum of the ones and the tens digit is ten. If the digits
Tema [17]

Answer:

The original number is 28

Step-by-step explanation:

start by listing all possible combinations of digits that give 10 when added:

19 (1+9=10)

28 (2+8 =10)

37 (3+7=10)

46 (4+6=10)

55 (5+5=10)

Look into the order of digits reversed and what the difference with the original number gives:

1)  19  reversed is 91 then when we subtract 91 - 19 we obtain 72

2) 28 reversed is 82 hen when we subtract 82 - 28 we obtain 54 which is the combination we where trying to find.

Notice as well, that as we go down the list, the differences between reversed digit number and original become smaller (and ends being zero for the number 55), so they do not satisfy the requirement.

Therefore 28 is the answer, since 82 (the new number formed when the digits are reversed) exceeds the original number by 54.

8 0
3 years ago
Read 2 more answers
For question 6 pls help show work step by step
Alexxx [7]

The steps are labeled, and the chart on the side is to help you know which numbers are x, and which ones are y.

6 0
4 years ago
Question on picture attached, easy but i’m stuck (need help asap)
Ludmilka [50]

Answer:

∠CDF = 54

Step-by-step explanation:

In ΔAEB,

AE ≅ AB

∠ABE = ∠E  = x   {Angles opposite to equal sides are equal}

∠EAB + ∠E +∠ABE = 180  {angle sum property of triangle}

  26  + x + x  = 180

      26 + 2x = 180

              2x = 180 - 26

             2x = 154

               x = 154/2

x = 77

∠ABE = ∠E = 77

In quadrilateral AECF

∠A + ∠E + ∠C + ∠F = 360

90 + 77 + ∠C  + 90 = 360

                ∠C + 257 = 360

                        ∠C = 360 - 257

    ∠C = 103

∠FCD + ∠BCD  = ∠C

∠FCD +  67 =  103

        ∠FCD = 103 - 67

        ∠FCD  = 36

ΔFCD,

∠FCD + ∠CDF + ∠CFD = 180

36 + ∠CDF + 90 = 180

       ∠CDF + 126 = 180

                   ∠CDF = 180 - 126

                  ∠CDF = 54

7 0
3 years ago
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