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Mama L [17]
2 years ago
13

Find the solution to the system of equations.

Mathematics
1 answer:
yawa3891 [41]2 years ago
5 0

Answer:

x = 1, y = -4

Step-by-step explanation:

set each equation equal:

-7x + 3 = -x - 3

-6x + 3 = -3

-6x = -6

x = 1

y = -7 + 3

y = -4

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6 0
2 years ago
WILL MARK BRAINLIEST!!! Find the fifth roots of 243(cos 240° + i sin 240°).
Snowcat [4.5K]

Answer:

<h2>3(cos 336 + i sin 336)</h2>

Step-by-step explanation:

Fifth root of 243 = 3,

Suppose r( cos Ф + i sinФ) is the fifth root of 243(cos 240 + i sin 240),

then r^5( cos  Ф  + i sin  Ф )^5 = 243(cos 240 + i sin 240).

Equating equal parts and using de Moivre's theorem:

r^5 =243  and  cos  5Ф  + i sin  5Ф = cos 240 + i sin 240

r = 3 and  5Ф = 240 +360p so Ф =  48 + 72p

So Ф = 48, 120, 192, 264, 336  for   48 ≤ Ф < 360

So there are 5 distinct solutions given by:

3(cos 48 + i sin 48),

3(cos 120 + i sin 120),

3(cos 192 + i sin 192),

3(cos 264 + i sin 264),

3(cos 336 + i sin 336)

6 0
2 years ago
Perform the indicated operation and write the answer in the form a + bi. (–1 + 5i) + (3 + 7i)
pashok25 [27]

Answer:

12i + 2

Step-by-step explanation:

Combine like terms.

-1 + 3 = 2

5i + 7i = 12i

12i + 2 is your answer.

~

5 0
3 years ago
What is the formula for surface area
zubka84 [21]
The area is perimeter times height plus area of the bases
6 0
3 years ago
Read 2 more answers
If a jogger runs 2 miles and burns 185 calories, how many calories would he burn if he jogged 3 miles?
aliina [53]

The total amount of calories burnt in jogging 2 miles = 185 calories

We have to determine the number of calories burned in jogging 3 miles.

Firstly, we will determine the amount of calories burnt in jogging 1 mile. We will use unitary method to evaluate this.

So, the total amount of calories burnt in jogging 1 mile = 185 \div 2

= 92.5 calories

So, the amount of calories burnt in 3 miles = 3 \times 92.5

= 277.5 calories

Therefore, 277.5 calories are burned in jogging 3 miles.

6 0
3 years ago
Read 2 more answers
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