Answer:
<h2>3(cos 336 + i sin 336)</h2>
Step-by-step explanation:
Fifth root of 243 = 3,
Suppose r( cos Ф + i sinФ) is the fifth root of 243(cos 240 + i sin 240),
then r^5( cos Ф + i sin Ф )^5 = 243(cos 240 + i sin 240).
Equating equal parts and using de Moivre's theorem:
r^5 =243 and cos 5Ф + i sin 5Ф = cos 240 + i sin 240
r = 3 and 5Ф = 240 +360p so Ф = 48 + 72p
So Ф = 48, 120, 192, 264, 336 for 48 ≤ Ф < 360
So there are 5 distinct solutions given by:
3(cos 48 + i sin 48),
3(cos 120 + i sin 120),
3(cos 192 + i sin 192),
3(cos 264 + i sin 264),
3(cos 336 + i sin 336)
Answer:
12i + 2
Step-by-step explanation:
Combine like terms.
-1 + 3 = 2
5i + 7i = 12i
12i + 2 is your answer.
~
The area is perimeter times height plus area of the bases
The total amount of calories burnt in jogging 2 miles = 185 calories
We have to determine the number of calories burned in jogging 3 miles.
Firstly, we will determine the amount of calories burnt in jogging 1 mile. We will use unitary method to evaluate this.
So, the total amount of calories burnt in jogging 1 mile = 
= 92.5 calories
So, the amount of calories burnt in 3 miles = 
= 277.5 calories
Therefore, 277.5 calories are burned in jogging 3 miles.
