Question

The Taylors plan to expand their

Answer 1

Answer:

$A_{2} = 720\ ft^{2}$

Step-by-step explanation:

Let w and l be the width and length of the garage.

Let $A_{1}$ and $A_{2}$ be the area of garage at present and new garage.

Given:

The area of the garage at present

$A_{1}=80\ ft^{2}$

And he planed to tripling the dimensions of the garage.

We need to find the area of the new garage.

Solution:

We know the area of the rectangular garage.

$Area=width\times lendth$

$A_{1}=w\times l$

$w\times l=80$ ---------------(1)

The dimension of the new garage is triple, so the area of the new garage is.

$A_{2} = (3\times width)\times (3\times length)$

$A_{2} = (3\times w)\times (3\times l)$

$A_{2} = 9\times (w\times l)$

Substitute $w\times l=80$ from equation 1.

$A_{2} = 9\times (80)$

$A_{2} = 720\ ft^{2}$

Therefore, the area of the new garage $A_{2} = 720\ ft^{2}$