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SOVA2 [1]
3 years ago
15

If we compare and contrast electromagnetic waves with sound waves, all BUT one statement is true. That is A) sound waves require

a medium to travel while electromagnetic waves do not. B) electromagnetic waves can travel through the vacuum of space while sound waves cannot. C) electromagnetic waves must have a medium in which to travel, but sound waves can travel anywhere. D) sound waves must bounce off of matter in order to travel while electromagnetic waves do not require matter to be present.
Physics
2 answers:
ehidna [41]3 years ago
6 0

its c electromagnetic waves must have a medium in which to travel, but sound waves can travel anywhere.

Aleks04 [339]3 years ago
5 0

The only incorrect statement is

C) electromagnetic waves must have a medium in which to travel, but sound waves can travel anywhere.

Electromagnetic waves do not require a medium to travel. they can travel through vacuum also. for example:- light wave is an electromagnetic wave and it can travel through vacuum also.

On the other hand, sound wave require a medium to travel. sound waves can not travel through vacuum.

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Last week we investigated the black hole at the center of our galaxy, with massMX= 8.5×1036kg. An object whose size is on the or
swat32

Answer:

d=2.38*10^{13}m

Explanation:

We know the mass of the hole, so we define as,

M_x= {8.5*10^{36}}kg

For which centripetal force is equal to gravitational force

\frac{mv^2}{r}=\frac{GMm}{d^2}

Angular velocity is equal to v/r,

w^2r=\frac{6.67*10^{-11}*8.5*10^{36}}{d^2}

As r=1 and w=1, we clear to d,

d^2=5.6695*10^{26}m

d=2.38*10^{13}m

6 0
4 years ago
A particle moves along the x axis. It is initially at the position 0.270 m, moving with velocity 0.140 m/s and acceleration 20.3
mixas84 [53]

Answer:

a) -2.34 m

b) -1.3 m/s

c) 0.056 m

d) 0.320 m/s

Explanation:

part a

Given:

s(0) = 0.27 m

v(0) = 0.14 m/s

a = -0.320 m/s^2

t = 4.50s

Using kinematic equation of motion for constant acceleration:

s (t) = s(0) + v(0)*t + 0.5*a*t^2

s ( 4.5 s ) = 0.27 + 0.14*4.5 + 0.5*-0.32*4.5^2

s(4.5) = -2.34 m

part b

Using kinematic equation of motion for constant acceleration:

v(t) = v(0) + a*t

v(4.5s) = (0.14) + (-0.32)(4.5) = -1.3 m/s

part c

Use equation for simple harmonic motion:

s(t) = A*cos(w*t)

v(t) = -A*w*sin (w*t)

a(t) = -A*(w)^2 * cos (w*t)

0.27 m = A*cos(w*t)   .... Eq 1

0.14 m/s = - A*w*sin (w*t)  .....Eq2

-0.320 = -A*(w)^2 * cos (w*t)   .... Eq3

Solve the three equations above for A, w, and t

Divide 1 and 3:

w^2 = 0.32 / 0.27

w = 1.0887 rad / s

Divide 2 and 1:

w*tan(wt) = 0.14 / 0.27

tan(1.0887*t) = 0.476289

t = 0.4083 s

A = 0.27 / cos (1.0887*0.4083) = 0.3 m

Hence, the SHM is s(t) = 0.3*cos(1.0887*t)

s(4.5) = 0.3*cos(1.0887*4.5) = 0.056 m

part d

v(t) = - 0.32661 * sin (1.0887*t)

v(4.5) = - 0.32661 * sin (1.0887*4.5) = 0.320 m/s

3 0
3 years ago
When all the forces on an object are equal and opposite, & the net force is zero, that's..
Serggg [28]

That would be a balanced force because the forces cancel each other out.

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3 years ago
The following table shows the duration of a year on some unknown planets of equal mass. Duration of Year Planet Duration of Year
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Gravitational force between sun and planet is given by,

F=\frac{GMm}{r^{2}}

Thus, The force of gravitation is inversely proportional to the distance.

Kepler's law states that the square of period of planet is proportional to cube of semi major axis of its orbit.

The time period of planet is more when the gravitational force is less.

Thus, planet Y is closer to earth because sun exert greater gravitational force than planet Z.

8 0
4 years ago
Read 2 more answers
What is the relationship between "friction" and "thermal energy?"
SCORPION-xisa [38]
When temperature increases, particles in an object speed up, which means an increase in thermal energy<span>. Since the particles are moving more now, the potential energy decreases, therefore kinetic energy increases. Overall,when temperature go up, thermal energy go up, which leads to an increase to kinetic energy.</span>
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3 years ago
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