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vladimir2022 [97]
3 years ago
7

A hailstone traveling with a velocity of 43 meters per second comes to a virtual stop at 0.28 seconds after hitting water.what i

s the magnitude of it acceleration in water
Physics
1 answer:
-Dominant- [34]3 years ago
7 0
Magnitude of acceleration = (change in speed) / (time for the change)

Change in speed = (final speed) minus (initial speed)

                               =  ( zero )          minus  (43 m/s) =  - 43 m/s .

Magnitude of acceleration = ( - 43 m/s ) / (0.28 sec)  =  - 153.6 m/s²

                                                                                  (about  - 15.7 G's) 
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because it's on an upward climb therefore newton's law of motion is in place and you're car is pulled by gravity

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Which of the following is occurring while a satellite is in orbit around Earth? O It is continuously pulling away from Earth It
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since gravity from earth is the thing that keeps it constantly in orbit

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A uniform thin circular rubber band of mass M and spring constant k has an original radius R?
Gemiola [76]

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Question 10 of 10
Bad White [126]

Answer:

D. The Federal Reserve Bank can provide a short-term loan to banks

to prevent them from running out of money.

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A bank run occurs when a large number of depositors withdraw their deposits simultaneously from a bank.

As the number of withdraws increases, the available cash in the bank decreases until a point that the bank can't give depositors their money.

In these situations, The Federal Reserve Bank acts as a lender of last resort that helps to reinforce the effect of deposit insurance, and to reassure bank customers that they will not lose their money.

5 0
4 years ago
A sports car traveling along a straight line increases its speed from 19.8 mi/h to 59.9 mi/h.a. What is the ratio of the final t
Natasha2012 [34]

Answer

given,

initial speed of the car (v₁)= 19.8 mi/h

final speed of the car (v₂)= 59.9 mi/h

a) initial momentum = m v₁

                   P₁ = 19.8 m

  final final momentum = m v₂

                   P₂ = 59.9 m

      ratio = \dfrac{P_2}{P_1}

              =\dfrac{59.9 m}{19.8 m}

      ratio of momentum=\dfrac{P_2}{P_1}=3.025

b) initial kinetic energy= 1/2 m v₁²

                   K₁ = 196.02 m

  final kinetic energy= 1/2 m v₂²

                   K₂ = 1794.005 m

      ratio = \dfrac{K_2}{K_1}

              =\dfrac{1794.005 m}{196.02 m}

      ratio of Kinetic energy=\dfrac{P_2}{P_1}=9.15

8 0
3 years ago
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