To solve this problem you must apply the proccedure shown below:
1. You have the following information given in the problem above:
- The <span>spherical bubble gum ball is at the bottom
- The radius of the cone is 1.5 inches, and its height is 3 inches.
- The diameter of the bubble gum ball is 0.5 inches.
2. Therefore, you must apply the formula for calculate the volume of a sphere to find the volume of the bubble gum ball:
Vs=4</span>πr^3/3
r is the radius (r=0.5 inches/2=0.25 inches)
Vs=4π(0.25 inches)^3/3
Vs=0.065 inches^3
3. The volume of the cone is:
Vc=πr^2h/3
r is the radius of the cone (r=1.5 inches)
h is the height (h= 3 inches)
Vc=π(1.5 inches)^2(3 inches)/3
Vc=7.06 inches^3
W<span>hat is the closest approximation of the volume of the cone that can be filled with flavored ice?
Vt=Vc-Vs
Vt</span>≈7.00 inches^3
D = adult
c = child
t = total admission cost
t = 8d + 5c
t = 8(2) + 5(3) = $31
Answer:
4 times c is 4c and 4 times 3 is 12 so the answer would be 4c + 12
Step-by-step explanation:
No, if you find the common denominator of 8, 1/2 will turn into 4/8, which is greater than 1/8. Therefore 1/8 is less than 1/2.
Answer:
140 cm³
Step-by-step explanation:
volume = (6×½×3×2.6) × 6= 23.4×6
=140.4 = 140 cm³