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3 years ago

An ostrich can run at a rate of 50 miles in 60 minutes.

1 answer:

defon3 years ago

7 0

So 50 miles/60 minutes and you basically just convert it
you want to divided by 10 so you will get
5miles/6minutes
and then multiply both by 3 and you will get 18

so it takes 18 minutes

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Trish has 7 cans of dog food for 3 days. She will feed each dog 2 1/3 cans of food each days. If she wants to feed them 3 cans e

Minchanka [31]

Answer:

2 more cans

Step-by-step explanation:

2 1/3 x 3 = 7 cans (this the amount of cans of dog food she has)

3 x 3 = 9

the 3 represents how she wants to feed 3 cans of dog food each day for 3 days; the other 3 represents 3 days

9 - 7 = 2

7 0

2 years ago

The area of a rectangle is represented by the expression 6x³y5. Which of the following could be the

oee [108]

The length and width of the rectangle are: $2x^2y^2 , 3xy^3$

<h3>What is the area of the rectangle?</h3>

The area of the rectangle is the product of the length and width of a given rectangle.

The area of the rectangle = length × Width

The area of a rectangle is represented by the expression $6x^3y^5$ .

The area of the rectangle = $2x^2y^2 \times 3xy^3$

= $6x^3y^5$

So, the length and width of the rectangle are: $2x^2y^2 , 3xy^3$

Learn more about the area;

brainly.com/question/1658516

#SPJ1

7 0

1 year ago

Assuming there are an equal amount of houses per street, if there are 18 houses on 3 streets, how many houses are there per stre

N76 [4]

Answer:

Step-by-step explanation:

3 0

3 years ago

Solve y=f(x) for x. Then find the input when the output is -3.

DochEvi [55]

Answer:

Please check the explanation

Step-by-step explanation:

Given the function

$f\left(x\right)\:=\:\left(x-5\right)^3-1$

Given that the output = -3

i.e. y = -3

now substituting the value y=-3 and solve for x to determine the input 'x'

$\:\:y=\:\left(x-5\right)^3-1$

$-3\:=\:\left(x-5\right)^3-1\:\:\:$

switch sides

$\left(x-5\right)^3-1=-3$

Add 1 to both sides

$\left(x-5\right)^3-1+1=-3+1$

$\left(x-5\right)^3=-2$

$\mathrm{For\:}g^3\left(x\right)=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}$

Thus, the input values are:

$x=-\sqrt[3]{2}+5,\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}-i\frac{\sqrt[3]{2}\sqrt{3}}{2},\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}+i\frac{\sqrt[3]{2}\sqrt{3}}{2}$

And the real input is:

$x=-\sqrt[3]{2}+5$

$x=3.74$

4 0

2 years ago

PLS ANSWER RN

Rzqust [24]

Answer:

So, the answer in short is B) (6,1)

Step-by-step explanation:

If you graph the points, then you see that point A is 8 points away from point B on the X-axis. If you take 8 and divide it by 4, you get 2, so that means that the 1/4 way point is 2 points away from point A, giving you 6 as your x-axis point for this new point. B is the only one with 6 as its spot on the x axis, leaving B as the only choice. BTW you're pretty cute ;)

6 0

3 years ago

Read 2 more answers