All categories

3 years ago

solve the system of equations below by graphing both equations with a pencil and paper y = x + 1 y = 1/2x + 3

Mathematics

2 answers:

Brut [27]3 years ago

8 0

You can use desmos! and to solve you find the point(s) where they overlap

dlinn [17]3 years ago

8 0

Answer:

(4,5)

Step-by-step explanation:

You might be interested in

How many times does 20 go into 74??

Dima020 [189]

About three times. Just divide 74 by 20 which is 3 but exactly it is 3.7.
hoped it helped

7 0

3 years ago

Read 2 more answers

39. Kate recorded the time it took six children of

scZoUnD [109]

Answer:

$y=-11x+261$

Step-by-step explanation:

As you can observe in the image attached, the line that best fits passes through point B and C. That means we can use those point to find the slope of such line.

$m=\frac{y_{2} -y_{1} }{x_{2}-x_{1} }$

Where $B(11,137)$ and $C(12,126)$

$m=\frac{126-137}{12-11}=-11$

So, the slope of the line that best fits is -11, approximately.

Now, we use the point-slope formula to find the equation.

$y-y_{1} =m(x-x_{1} )\\y-137=-11(x-11)\\y=-11x+124+137\\y=-11x +261$

Therefore, the line that best fits is $y=-11x+261$ approximately.

Remember, when we estimate a line for some data on a scatterplot, we are calculating an approximation, that's why we also said "approximately", because the line is an approximation where the majority of point meet.

4 0

3 years ago

Pls help I need a good grade

Nikitich [7]

Answer:

If it is number 5. the answer is 13

Step-by-step explanation:

take the largest number and subtract the smallest number.

7 0

3 years ago

Read 2 more answers

Mary must choose a new password where the first and last choices are possibly repeated lowercase letters; the second and third

Salsk061 [2.6K]

The number of ways she can choose a password is 3986236800

<h3>In how many ways can she choose a password?</h3>

The given parameters and the possible selection of characters are:

First and last choices are possibly repeated lowercase letters;

There are 26 lower characters.

Since the characters can be repeated, then we have

First = 26

Last = 26

The second and third positions must be distinct uppercase letters

There are 26 upper characters.

Since the characters are distinct, then we have

Second = 26

Third = 25

The fourth position must be a # , $, or & symbol;

So, we have

Fourth = 3

The next four positions are distinct nonzero digits.

There are 9 nonzero digits.

Since the digits are distinct, then we have

Next = 9, 8, 7, 6

The number of ways she can choose a password is

Ways = First * Second * Third * Fourth * Next * Last

So, we have

Ways = 26 * 26 * 25 * 3 * 9 * 8 * 7 * 6 * 26

Evaluate the product

Ways = 3986236800

Hence, the number of ways she can choose a password is 3986236800