Given that the triangle is a right angled triangle, to solve for x we shall use the Pythagorean theorem given by:
c^2=a^2+b^2
where:
c is the hypotenuse
a and b are the legs.
c=10
a=6
b=(x-6)
thus plugging the values in the equation and solving for x we get:
10^2=6^2+(x-6)^2
100=36+x^2-12x+36
100=x^2-12x+72
0=x^2-12x-28
factoring the above we get:
0=(x+2)(x-14)
hence
x=-2 or x=14
given that there is no negative distance then
x=14
thus the value of x is 14
BE is congruent to overline CF since they are altitudes of the same trapezoid(S).
AB is congruent to overline CD (Given)
AE is congruent to overline FD by the Hypotenuse Leg Theorem.
triangle ABC is congruent to triangle DCF (SSS Triangle Congruence)
angle A is congruent to angle D since corresponding parts of congruent triangles are congruent.
Answer:
Step-by-step explanation: its yo mama :)
