solve the system of equations below by graphing both equations with a pencil and paper y = x + 1 y = 1/2x + 3
2 answers:
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Answer:
Ф =
Step-by-step explanation:
It is a bit difficult to input the work here, so I uploaded an image
- First we can use the trig identities to change sec²(Ф) to tan²(Ф) + 1
- Then we can combine like terms
- Then we can factor this as a polynomial function
- Then we can set each term equal to zero and solve for Ф
- The first term tan(Ф) - 2 = 0 has no solution because tan(Ф) ≠ -2 anywhere
- The second term tan(Ф) - 1 = 0 has two solutions of
and
so these are the solutions to the problem
Answer:
A) The applicant's SAT z-score has to be positive and large.
Step-by-step explanation:
The zscore measures how much above or below the mean a value is in a normally distributed sample. The value can be a grade, for example.
In a set with mean and standard deviation
, the zscore of a measure X is given by
.
When the zscore of X is negative and large, this means that the grade is on the very low side(very below the mean).
When the zscore of X is negative and small, this means that the grade is on the low side(a bit below the mean).
When the zscore of X is close to 0, the grade is close to the mean.
When the zscore of X is positive and small, this means that the grade is on the high side(a bit above the mean).
When the zscore of X is positive and large(Z > 1), this means that the test score is on a very high side.
The problem states that:
To get admitted to top universities, the applicant's SAT (Scholastic Aptitude Test) score must be on a very high side. So, the correct answer is:
A) The applicant's SAT z-score has to be positive and large.