Answer:
1
Step-by-step explanation:
The denominator in 9 is one. This also applies for all numbers without a denominator.
Hope this helps :)
87 and 93
45 and 135
74 and 106
Answer:
The interval that would represent the middle 68% of the scores of all the games that Riley bowls is (147, 173).
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
Approximately 68% of the measures are within 1 standard deviation of the mean.
Approximately 95% of the measures are within 2 standard deviations of the mean.
Approximately 99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean of 160, standard deviation of 13.
Middle 68% of the scores of all the games that Riley bowls.
Within 1 standard deviation of the mean, so:
160 - 13 = 147.
160 + 13 = 173.
The interval that would represent the middle 68% of the scores of all the games that Riley bowls is (147, 173).
Since order does not matter, you use a combination and not a permutation, so the first one is true, which means the second one is not true.
The probability of choosing two diamonds and three hearts can be represented by (13C2 * 13C3)/52C5, which is 0.0086, not 0.089, so the third one is not true.
The probability of choosing five spades and the probability of choosing five clubs are represented by the same thing, 13C5/52C5, which is roughly 0.0005, so the fourth one is not true but the fifth one is. So the answer is the first and fifth one.
<u>Given:</u>
The angle of elevation from the point on the ground to the top of the tree is 34° and the point is 25 feet from the base of the tree.
We need to determine the height of the tree.
<u>Height of the tree:</u>
Let the height of the tree be h.
The height of the tree can be determined using the trigonometric ratio.
Thus, we have;

Substituting the values, we get;

Multiplying both sides by 25, we have;



Rounding off to the nearest tenth of a foot, we get;

Thus, the height of the tree is 16.9 feet.
Hence, Option B is the correct answer.