The area of a rectangle is 40 square feet. What could be the perimeter of the rectangle? how is this problem solved.
2 answers:
The side lengths to get an area of 40 could be 8 and 5
Area = length x width
So if one side is 8 and the other is 5 then it will have to be the same on the opposite side of the rectangle
Perimeter = side + side + side+ side
So it is 8+8+5+5 = 16+10 = 26 feet
This is just one answer, there is more than one correct answer for this problem
A possible perimeter for the rectangle would be 28
Area=L x W
40/10=4
Width=4, Length=10
Perimeter=L+L+W+W
4+4+10+10=28
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