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3 years ago

The slope of EF¯¯¯¯ is −5/2 .

Mathematics

1 answer:

stellarik [79]3 years ago

4 0

Answer:

LM and NP

Step-by-step explanation:

LM= 2/5

NP=2/5

GH= -5/2

JK= =5/2

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After a rotation of 90° about the origin, the coordinates of the vertices of the image of a triangle are A'(6,3), B'(-2, 1)

Fed [463]

Answer:

A(3, -6)
B(1, 2)
C(7, -1)

Step-by-step explanation:

Rotation by -90° about the origin is the transformation ...

(x, y) ⇒ (y, -x)

So, your pre-image points are ...

A'(6, 3) ⇒ A(3, -6)

B'(-2, 1) ⇒ B(1, 2)

C'(1, 7) ⇒ C(7, -1)

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3 years ago

A store sells 12-packs of ballpoint pens for $1.09 each and composition books for $2.79 each. Cindy buys m packs of ballpoint pe

Ludmilka [50]

<span>There are two possible ways where you can express this. First, is by presenting the equation net of 5 percent which is "x=1.0355n+2.6505m". The other way to express such is by presenting it with gross amount which is "x= (1-0.05)(1.09n+2.79m)"
</span>

5 0

3 years ago

Read 2 more answers

What is AB in the figure?

blsea [12.9K]

Answer

B is the answers

Step-by-step explanation:

5 0

2 years ago

The Fish and Game Department stocked a lake with fish in the following proportions: 30% catfish, 15% bass, 40% bluegill, and 15%

vagabundo [1.1K]

Answer:

1) $\chi^2 =\frac{(112-150)^2}{150}+\frac{(95-75)^2}{75}+\frac{(210-200)^2}{200}+\frac{(83-75)^2}{75}=16.313$

2) $p_v =P(\chi^2_{3}>16.313)=0.000978$

And we got the same decision reject the null hypothesis at 5% of significance.

Step-by-step explanation:

Previous concepts

The Chi-Square test of independence is used "to determine if there is a significant relationship between two nominal (categorical) variables". And is defined with the following statistic:

$\chi^2 =\sum_{i=1}^n \frac{(O-E)^2}{E}$

Where O rpresent the observed values and E the expected values.

State the null and alternative hypothesis

Null hypothesis: The distribution is 30% catfish, 15% bass, 40% bluegill, and 15% pike

Alternative hypothesis: The distribution is NOT 30% catfish, 15% bass, 40% bluegill, and 15% pike

The observed values are given by the table given:

Catfish =112, BAss = 95, Bluegill=210, Pike=83

Calculate the expected values

In order to calculate the expected values we can use the following formula for each cell of the table

$E = \% Grand total$

$E_{Catfish}=500*0.3=150$

$E_{Bass}=500*0.15=75$

$E_{Bluegill}=500*0.4=200$

$E_{Pike}=500*0.15=75$

Part 1: Calculate the statistic

$\chi^2 =\frac{(112-150)^2}{150}+\frac{(95-75)^2}{75}+\frac{(210-200)^2}{200}+\frac{(83-75)^2}{75}=16.313$

$\chi^2 =16.313$

Calculate the critical value

First we need to calculate the degrees of freedom given by:

$df= (categories-1)=(4-1)= 3$

Since the confidence provided is 95% the significance would be $\alpha=1-0.95=0.05$ and we can find the critical value with the following excel code: "=CHISQ.INV(0.95,3)", and our critical value would be $\chi^2_{crit}=7.815$

We can calculate also the p value:

$p_v =P(\chi^2_{3}>16.313)=0.000978$

And we got the same decision reject the null hypothesis at 5% of significance.

5 0

2 years ago

If AB = BC in traingle ABC, then which of the following must be true?

Nata [24]

Number one should be the right answer.

6 0

3 years ago

Read 2 more answers