Ask question

Ask question

All categories

3 years ago

13

Can yesterday's weather map help you predict tomorrow's weather? Give a reason for your answer

1 answer:

BartSMP [9]3 years ago

7 0

Yesterday's weather map can be very useful when it comes to predicting the weather for tomorrow, but it also might not be useful at all. The reason why we can not say it for sure would it help or not is because it all depends on the scale of the weather map. If the weather map is only showing us smaller area, then we will not be aware of the surrounding area's weather conditions, and considering how quickly the air masses move, everything can change very quickly. On the other hand, if we have a weather map that presents us much larger area, then we can see the surrounding area and its weather characteristics, so even if the reader of the map is not professional, still it will be able to make a fairly accurate prediction.

You might be interested in

Who is followers of khadijah hashmi

Doss [256]

Answer:

not .

Explanation:

.......

7 0

3 years ago

Read 2 more answers

Position of Nigeria in geography

kkurt [141]

Nigeria is a country in West Africa.

5 0

3 years ago

Many countries in Southwest Asia and Northern Africa have large numbers of people per unit of arable land, or high _____________

KIM [24]

Answer:

The correct answer would be population density.

Explanation:

3 0

3 years ago

What was one of the things that brought tourist to visit the alps in france?

zvonat [6]

One of the things that brought tourists to France, was the beautiful scenery and nature

5 0

3 years ago

You are told that PA I B) = PBIA). Which statement below must be true?

ivann1987 [24]

Answer:

A and B are equally likely

Explanation:

The conditional probability is defined as follows:

$P(X|Y)=\frac{P(X\cap Y)}{P(Y)}$

where:

$P(X|Y)$ is the probability for X to occur, given that Y has occurred

$P(X\cap Y)$ is the probability that both X and Y occur at the same time

$P(Y)$ is the probability for Y to occur

Given two events A and B, we have:

$P(A|B)=\frac{P(A\cap B)}{P(B)}$

and

$P(B|A)=\frac{P(A\cap B)}{P(A)}$

In this problem, we are told that

$P(A|B)=P(B|A)$

Which means that:

$\frac{P(A\cap B)}{P(B)}=\frac{P(A\cap B)}{P(A)}$

Simplifying, we get:

$P(A)=P(B)$

which means that A and B are equally likely.

4 0

3 years ago