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Ad libitum [116K]
3 years ago
7

A study by a group of cardiologists determined that maximal heart rate in humans, a parameter used as a basis for prescribing ex

ercise programs, depends on age. Maximal heart rate is around 201 beats per minute for a 10-year-old, and decreases at a constant rate of 7 every 10 years. Which of the following inequalities best describes the ages, for which maximal heart rate is less than 180, a is >or equal to 10.. HELP

Mathematics
1 answer:
aksik [14]3 years ago
5 0

Answer:

208 - 0.7a < 180

Step-by-step explanation:

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Answer:

The 95% confidence interval for the true proportion is given on this case by (0.6457 , 0.8489)

For this case we can starting calculating an estimation for the proportion like this:

\hat p =\frac{0.6457 +0.8489}{2} = 0.7473

And we can calculate the margin of error like this:

ME= Upper -\hat p = 0.8489- 0.7473= 0.10106

ME= \hat p -Lower = 0.7473- 0.6457= 0.10106

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by and . And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

The 95% confidence interval for the true proportion is given on this case by (0.6457 , 0.8489)

For this case we cab starting calculating an estimation for the proportion like this:

\hat p =\frac{0.6457 +0.8489}{2} = 0.7473

And we can calculate the margin of error like this:

ME= Upper -\hat p = 0.8489- 0.7473= 0.10106

ME= \hat p -Lower = 0.7473- 0.6457= 0.10106

5 0
3 years ago
Find the value of<br>a.) lim (x²-1)/(x²+1)<br>x−&gt;∞<br>​
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Answer:

\displaystyle\lim_{x \to \infty} \frac{x^2-1}{x^2+1} \\ \text{take $x^2$ common from numerator and denominator} \\ \displaystyle\lim_{x \to \infty} \dfrac{1-\frac{1}{x^2}}{1+\frac{1}{x^2}} \\\text{Now put the limit}\\\displaystyle\lim_{x \to \infty} \frac{1-0}{1+0}= 1

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3 years ago
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