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arsen [322]
4 years ago
6

Hey guys cannu please help asap i will do anythying

Mathematics
2 answers:
makkiz [27]4 years ago
4 0
25. C
26. C

Hope this helps!
koban [17]4 years ago
3 0
25 is B and 26 is C because the first is (2,1) so (7,1) and then (2,5) so (7,5)so it can form a rectangle and 26 be when reflected across the y axis the -2 will change to 2 and then it will be (2,9) but then when you reflect it to the x axis the 9 will turn into -9 then (2,-9)
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BARSIC [14]

Answer:

21

Step-by-step explanation:

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3 years ago
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Four circles of unit radius are drawn with centers $(1,0)$, $(-1,0)$, $(0,1)$, and $(0,-1)$. a circle with radius 2 is drawn wit
Reika [66]
Check the picture 1.

The regions contained in an odd number of these 5 circles are

the pink colored region, contained only in the circle with radius 2, 

and the yellow regions, each contained in the intersection of 2 small circles and the third large circle.

So what we need to determine is the "area pink + area yellow".


Consider the second picture.

Let A2 be the area of the right isosceles triangle, and A1 be half of the yellow region.

the region A2 + A1 is called a sector, and it is 1/4 of the area of a unit circle.

A1=A_{sector}-A2= \frac{1}{4} \pi r^2- \frac{1}{2}.1.1= \frac{1}{4} \pi 1^2- \frac{1}{2}=  \frac{1}{4}\pi- \frac{1}{2}


Thus, the overall yellow region is 8A1=8(\frac{1}{4}\pi- \frac{1}{2})=2\pi-4


The purple area is:
 
Area of large circle - 4*(Area of 1 small circle) + yellow region.

(because subtracting all 4 small circles means that each of the 4 separate yellow regions have been subtracted twice)

A_{purple}=\pi.2^2-4(\pi.1^2)+2\pi-4=4\pi-4\pi+2\pi-4=2\pi-4


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Answer:   6\pi-8    square units

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4 years ago
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y=−x2−36 y = − x 2 − 36

becomes

x=−y2−36 x = − y 2 − 36 .

Now, solve the equation

x=−y2−36 x = − y 2 − 36 for y y .

y=−x−36‾‾‾‾‾‾‾‾√ y = − x − 36y=−x−36‾‾‾‾‾‾‾‾√ y = − − x − 36

ANSWER y=−x−36‾‾‾‾‾‾‾‾√ y = − x − 36 y=−−x−36‾‾‾‾‾‾‾‾√
6 0
3 years ago
PLEASE HELP ASAP!! Complete the square to rewrite the following equation. Identify the center and radius of the circle. You must
r-ruslan [8.4K]

Answer:

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<u>Where</u>:

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<u>Rewriting the equation</u>:

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8 0
2 years ago
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Answer:

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