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3 years ago

Express the product in simplest form.

Mathematics

1 answer:

Romashka [77]3 years ago

4 0

$\frac{8}{2x+8} * \frac{ x^{2}-16 }{4}$

1. Cross cancel
$\frac{4}{2x+8}* \frac{ x^{2} -16}{1}$

2. Multiply numerators
4*x²-16 = 4x²-64

3. Multiply denominators
2x+8*1 = 2x+8

$\frac{4 x^{2} -64}{2x+8}$

4. Divide
$\frac{4 x^{2} -64}{2x+8} = 2x-8$

5. Simplify
2(x-4)

Answer is 2(x - 4)

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a pattern calls for green tiles and blue tiles in a ratio of 3 : 4. how many green tiles are needed if 100 blue tiles are used ?

kolbaska11 [484]

Answer:

75 green tiles

Step-by-step explanation:

Green : Blue = 3 : 4

3 : 4 = x : 100

Write as fractions

3/4 = x/100

Cross Multiply (numerator * denominator / numerator * denominator)

300 = 4x

Divide both sides of the equation by 4

x = 75

75 green tiles

Hope this helps :)

5 0

3 years ago

Last year, 11 students tried out for the

umka2103 [35]

136% increase I think

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3 years ago

How to find the perimeter of the triangle

Sliva [168]

Answer:

A. 26.2

Step-by-step explanation:

To find the perimeter of the triangle, you have to find the distances of all three lines and add them up.

Line AB

Let's start off by finding the distance of line AB.

We will use the formula, $d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ .

Point A is (-2,5) and Point B is (4,-3).

To substitute the values, it will get to $d = \sqrt{(4--2)^{2}+(-3-5)^{2}}$ which in other words is $d = \sqrt{(4+2)^{2}+(-3-5)^{2}}$ .

Now we have to solve the parenthesis to get $d = \sqrt{(6)^{2}+(-8)^{2}}$ .

Now we have to solve the exponents which would get to $d = \sqrt{36+64}$ .

Now we have to simplify the square root to $d = \sqrt{100}$ . In other words, that is $d = 10$ .

Line AB = 10

Line BC

Now let's find the distance of line BC.

We will use the same formula, $d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ .

Point B is (4,-3) and Point C is (0,-6).

To substitute the values, it will get to $d = \sqrt{(0-4)^{2}+(-6--3)^{2}}$ which in other words is $d = \sqrt{(0-4)^{2}+(-6+3)^{2}}$ .

Now we have to solve the parentheses to get $d = \sqrt{(-4)^{2}+(-3)^{2}}$ .

Now we have to solve the exponents which would get to $d = \sqrt{16+9}$ .

Now we have to simplify the square root to $d = \sqrt{25}$ . In other words, that is $d = 5$ .

Line BC = 5.

Line AC

Now let's fine the distance of line AC.

We will use the same formula, $d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ .

Point A is (-2,5) and Point C is (0,-6).

To substitute the values, it will get to $d = \sqrt{(0--2)^{2}+(-6-5)^{2}}$ which in other words is $d = \sqrt{(0+2)^{2}+(-6-5)^{2}}$ .

Now we have to solve the parentheses to get $d = \sqrt{(2)^{2}+(-11)^{2}}$ .

Now we have to solve the exponents which would get to $d = \sqrt{4+121}$ .

Now we have to simplify the square root to $d = \sqrt{125}$ . In other words, that is $d = 5\sqrt{5}$ . To round that, $d = 11.2$ .

Line AC = 11.2.

Perimeter of Triangle ABC

Perimeter of Triangle ABC = Line AB + Line BC + Line AC.

Perimeter of Triangle ABC = 10 + 5 + 11.2

Perimeter of Triangle ABC = 26.2

Hope this helped! If not, please let me know <3

3 0

3 years ago

The table shows the yardage for each team in their last football game. Who had the worst performance? A) Bears B) Lions C) Tiger

AlexFokin [52]

Is there a picture or a graph? Not enough info I’m sorry!

4 0

3 years ago

Read 2 more answers

What two numbers' sum=-4 and product=-2

n200080 [17]

Let a and b be the two numbers. Then

a + b = -4

a b = -2

Solve the second equation for b :

b = -2/a

Substitute this into the first equation:

a - 2/a = -4

Multiply both sides by a :

a² - 2 = -4a

Move 4a to the left side:

a² + 4a - 2 = 0

Use the quadratic formula to solve for a :

a = (-4 ± √(4² - 4(-2))) / 2

a = -2 ± √6

If a = -2 + √6, then

-2 + √6 + b = -4

b = -2 - √6

In the other case, we end up with the same numbers, but a and b are swapped.

7 0

3 years ago